Has normal (2n) amount of DNA;
Has twice (4n) the normal amount of DNA
Answer:
A. Average plant height increases with an increase in the concentration of sodium phosphate until the plants reach a maximum possible height.
Explanation:
The graph in the attachment section portrays the average height of plants (cm) on the y-axis plotted against the concentration of sodium phoshate (mg/L) on the x-axis. Based on the observation of the result in the graph, an increase in the concentration of phosphate caused an increase in the average plant height (as depicted by the upward-sloping line).
However, the plant's average height didn't go beyond 35cm despite an increase in concentration of phosphate. This is because the plants has reached a maximum possible height i.e. a height climax. Hence, they cannot grow taller than 35cm no matter the amount of external nutrients (sodium phosphate) supplied.
Therefore, the noticeable trend that can be used to make a conclusion is that average plant height increases with an increase in the concentration of sodium phosphate until the plants reach a maximum possible height.
Answer:
The intracellular is where enzymes need to perform optimally or near optimum.
Explanation:
The Km is the concentration of molecules where an enzyme performs at half of its maximum velocity (Vmax). Therefore, when molecules are near Km the enzyme is able to hydrolyze molecules nearer its Vmax.
q=0,78
To calculate the frequency of the allele we use the Hardy-Weinberg equation. The Hardy-Weinberg equation is used to calculate the genetic variation of a population at equilibrium. If the alleles are A and a, p is the frequency of the allele A and q is the frequency of the allele a. Hardy-Weinberg equation for alleles A and a:
p² + 2pq + q² = 1
p² is the frequency of the homozygous genotype AA, 2pq is the frequency of the heterozygous genotype Aa and q² is the frequency of the homozygous genotype aa.
p²+2pq+q²=(p+q)²=1
p+q=1
<span>If p=0,22 q=1-0,22=0,78</span>
