Assuming that the center of each circle is at point C and D, then both have a radius of 7cm. We know that the formula for solving area of the circle is A=pi*r².
Then we solve area of once circle multiplied by two to get the total area of the given circles. The solution is shown below:
C1 area=3.1416*7²
C1 area=153.9384 cm²
Summation of the area of circle C and D is shown below:
Sum area=2*153.9384
Sum area=307.8768cm²
The answer is 98pi.
7.44-6.26=1.18
1.18 in minutes is 78 minutes bc 1 hour is 60 minutes + 18 minutes is 78
Hope this helps :D
a)
Check the picture below.
b)
volume wise, we know the smaller pyramid is 1/8 th of the whole pyramid, so the volume of the whole pyramid must be 8/8 th.
Now, if we take off 1/8 th of the volume of whole pyramid, what the whole pyramid is left with is 7/8 th of its total volume, and that 7/8 th is the truncated part, because the 1/8 we chopped off from it, is the volume of the tiny pyramid atop.
Now, what's the ratio of the tiny pyramid to the truncated bottom?
Answer:
x=65
other angle= 165
Step-by-step explanation:
quadrilaterals always have a total of 360 degrees
because of this you can set up an equation and solve
360=90+40+x+(4x-95)
360=130+5x-95
360=35+5x
325=5x
65=x
plug this in to find missing angle
4(65)-95=165
