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Otrada [13]
2 years ago
7

A hiker yells out "Hello!" into a canyon. If the echo of their voice

Physics
1 answer:
Tasya [4]2 years ago
3 0
D 193 is the right answer if not try c because it is in between them both
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A milk truck carries milk with density 64.6 lb/ft3 in a horizontal cylindrical tank with diameter 12 ft. (a) Find the force exer
7nadin3 [17]

Answer:

F = 351×10³lb

Explanation:

Given the density

ρg = 64.6lb/ft³

Diameter d = 12ft

The tank is horizontally cylindrical. The vertical distance from the top to the bottom of the tank is h = 12ft

The pressure in the tank is

P = ρgh = 64.6 × 12 = 775.2lb/ft²

The force exerted on one end of the tank is therefore F = PA = 775.2 × πd² = 775.2π×12²

F = 351×10³lb.

4 0
3 years ago
a man is standing near the edge of a cliff 85 meters high. he throws a stone upward vertically with an intial velocity of 10 m/s
alex41 [277]

Answer:

h = 90.10 m

Explanation:

Given that,

A man is standing near the edge of a cliff 85 meters high, h₀ = 85 m

The initial speed of the stone, u = 10 m/s

The path followed by the projectile is given by :

h(t)=-4.9t^2+10t+85 ....(1)

For maximum height,

Put dh/dt = 0

So,

\dfrac{dh}{dt}=-9.8t+10=0\\\\t=\dfrac{10}{9.8}\\\\=1.02\ s

Put the value of t in equation (1).

h(t)=-4.9(1.02)^2+10(1.02)+85\\\\=90.10\ m

So, the maximum height of the stone is equal to 90.10 m.

5 0
3 years ago
A 40 kg bike traveling down the road has a negative acceleration. What is true of the force? A. It is positive B. It doesn't exi
Greeley [361]

Answer:

C. It is negative

Explanation:

Per Newton's second law, the net force is the mass times the acceleration:

∑F = ma

If the acceleration is negative, the net force is negative.

4 0
3 years ago
Read 2 more answers
3 نقطة (نقاط)
Molodets [167]

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force <em>P</em>. Let W_P be the work done by the force <em>P</em>. Then the total work done on the block is

W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}

5 0
2 years ago
Imagine that you are a gas particle and that the material you are in condenses and then freezes. From your point of view as a pa
Elis [28]
This isn't really detailed, but it gives you an idea:
 
-"I am a gas particle
-"WOW ITS GETTING REALLY COLD!!!
-"Slowly, I can't move as well, not as fast
-"I'm frozen (LET IT GO, LET IT GOOOOOO)

I hope this helps :)


4 0
3 years ago
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