Answer:
The car must move at 2 m/s to have a Ke of 2,000 Joules.
Explanation:
Mark me pls
Answer:
Take a look at the attachment below.
Explanation:
Answer:
- Amplitude = 5 cm (Heights)
- Wavelength (λ) = 40 cm
-
Wave speed (v) = 12 m/s (Approx)
- Time period (T) = 0.033 s (Approx)
- Maximum particle speed (V) = 9.43 m/s
Explanation:
1) Amplitude
Amplitude = 5 cm (Heights)
2) Wavelength (λ)
Wavelength (λ) = 40 cm
3) Wave speed
Wave speed (v) = √ t / μ
Wave speed (v) = √ 3.6 / [25x10⁻³]
Wave speed (v) = 12 m/s (Approx)
4) Time period (T)
Time period (T) = 1/f = (λ)/v
Time period (T) = 0.40m / 12
Time period (T) = 0.033 s (Approx)
5) Maximum particle speed (V)
Maximum particle speed (V) = Aw
Maximum particle speed (V) = [0.05x2x3.14] / 0.033
Maximum particle speed (V) = 9.43 m/s
Answer:
24m/s
Explanation:
here also use 2nd eq of motion
then we use our answer
The correct option will be
D. Time, initial velocity and final velocity
The Formula can be written as,
Acceleration=Final velocity-Initial Velocity/Time