How does an object move when it is subject to a steady centripetal force

Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *

Gelneren [198K]

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

5 0

3 years ago

A 500 kg rollercoaster car starts from rest at the top of a 10.0 m tall hill. it then travels down the track and up a loop. the

malfutka [58]

Speed of the roller coaster at the top of the loop= 7.67 m/s

Explanation:

using the law of conservation of energy

KEi + PEi= KEf + PEf

KEi= kinetic energy at the top of the hill=0 because the car is at rest there.

PEi= potential energy at the top of the hill

PEf= potential energy at the top of the loop

KEf= kinetic energy at the top of the loop

Also kinetic energy= 1/ 2m v² and potential energy= mgh

m= mass

h= height

v= velocity

so 0+ mghi = 1/2mv² + mg h

500 (9.8)(10)+ 1/2 (500) v²= 500 ( 9.8) (7)

49000+250 v²= 34300

250v²= 14700

v²=58.8

v=7.67 m/s

4 0

3 years ago

Four equal masses m are located at the corners of a square of side L, connected by essentially massless rods. Find the rotationa

skelet666 [1.2K]

Answer:

Explanation:

a )

Moment of inertial of four masses about axis that coincides with one side :

Out of four masses . location of two masses will lie on the axis so their moment of inertia will be zero .

Moment of inertia of the two remaining masses

= m L² + m L²

= 2 mL²

b )

Axis that bisects two opposite sides

Each of the four masses will lie at a distance of L / 2 from this axis so moment of inertia of the four masses

= 4 x m x ( L/2 )²

= 4 x mL² / 4

= m L² .

3 0

3 years ago

The primary 40-turn coil of an ideal transformer is supplied with 120 V (rms). If the rms voltage output of the secondary coil i

Svet_ta [14]

Answer:

No. of turns in secondary coil are 5.

Transformer Type: STEP DOWN TRANSFORMER

Explanation:

The relationship of the no. of turns in transformer secondary and primary coils with their voltages is known as the turn ration. The formula for turns ratio is as follows:

Np/Ns = Vp/Vs

where,

Np = No. of turns in primary coil = 40

Ns = No. of turns in secondary coil = ?

Vp = Voltage supplied to primary coil = 120 V

Vs = Voltage output of secondary coil = 15 V

Therefore,

40/Ns = 120 V/15 V

Ns = 40/8

TYPE OF TRANSFORMER:

Since, this transformer decreases the voltage value at the output. Hence it is a <u>STEP DOWN TRANSFORMER.</u>

7 0

4 years ago

A proton moves through a region containing a uniform electric field given by E with arrow = 54.0 ĵ V/m and a uniform magnetic fi

madreJ [45]

Answer:

acceleration is 9.58 × $10^{7}$ (- 14 ĵ + 51 k ) m/s

Explanation:

given data

uniform electric field E = 54.0 ĵ V/m

uniform magnetic field B = (0.200 î + 0.300 ĵ + 0.400 k) T

velocity v = 170 î m/s.

to find out

acceleration

solution

we know magnetic force for proton is

i.e = e (velocity × uniform magnetic field)

magnetic force = e (170 î × (0.200 î + 0.300 ĵ + 0.400 k) )

magnetic force = e (- 68 ĵ + 51 k ) ..................1

and now for electric force for proton i.e

= uniform electric field × e ĵ

electric force = e (54 ĵ ) ............2

so net force will be add magnetic force + electric force

from equation 1 and 2

e (- 68 ĵ + 51 k ) + e (54 ĵ )

e (- 14 ĵ + 51 k )

so the acceleration (a) for proton will be

net force = mass × acceleration

a = e (- 14 ĵ + 51 k ) / 1.6 $10^{-19}$ / 1.67 × $10^{-27}$

acceleration = 9.58 × $10^{7}$ (- 14 ĵ + 51 k ) m/s

7 0

3 years ago