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Oksana_A [137]
3 years ago
7

Use the tests for divisibility to determine which numbers divide evenly into the given number. 39,960

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

  39,960 is divisible by all of the listed numbers.

Step-by-step explanation:

The sum of digits is 3+9+9+6+0 = 27, and the sum of those digits is 2+7=9.

This tells you the number is divisible by 3 and 9.

The number is even and ends in 0. Together with divisibility by 3, this tells you the number is divisible by 6. The 0-ending tells you the number is divisible by 2 and 5 and 10.

The last two digits are 60, a number that is divisible by 4, so the number is divisible by 4.

39,960 is divisible by all of the numbers listed: 2, 3, 4, 5, 6, 9, 10.

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3 years ago
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If z varies directly with x and inversely with the cube of y, when x=8,y=2 and z=3, what is x when y=4 and z=9/32?
Degger [83]
\bf \qquad \qquad \textit{double proportional variation}
\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{\underline{z} varies directly with \underline{x} and inversely with the cube of \underline{y}}\qquad  z=\cfrac{kx}{y^3}

\bf \textit{we also know that }
\begin{cases}
x=8\\
y=2\\
z=3
\end{cases}\implies 3=\cfrac{k8}{2^3}\implies 3=\cfrac{8k}{8}\implies 3=k
\\\\\\
therefore\qquad \boxed{z=\cfrac{3x}{y^3}}
\\\\\\
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4 years ago
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\huge\boxed{80}

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\boxed{80}

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3 years ago
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Triss [41]

Answer:

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