Answer:
8
Step-by-step explanation:
Formula for height of triangle
A÷BX2
In this case, 48÷12=4×2=8
Hope you understand ☺️
The weight of each pie will be 6 and 8 pounds respectively if the ratio of the seeds in these piles 3:4
<h3>What is the ratio?</h3>
It is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
We have:
A greedy hamster hoarded 2 piles of sunflower seeds. Yesterday the ratio of the seeds in these piles was 3:4
Let 3x and 4x are the seeds from the smaller and bigger pile.
= 4x + 2 (greedy hamster placed another 2 pounds of seeds in the bigger pile)
= 3x - 1/4 (ate 1/4 pound from the smaller pile)
4x + 2 = 5x
Because the quantities of seeds in those piles is in the ratio of 5:16
After solving:
x = 2
Smaller pile weight = 3x = 3(2) = 6
Bigger pile wieght = 4x = 4(2) = 8
Thus, the weight of each pie will be 6 and 8 pounds respectively if the ratio of the seeds in these piles 3:4
Learn more about the ratio here:
brainly.com/question/13419413
#SPJ1
Answer:
27KG
Step-by-step explanation:
Mouse- M , Cat - C, Dog - D
M + C = 10 ----- (1)
M + D = 20 -------(2)
C + D = 24 --------(3)
(1) - (2) => C - D = -10 ---- (4)
(3) + (4) => 2C = 14
=> C = 7
Substitute C in (1) => M + 7 = 10
=> M = 3
Substitute M in (2) => 3 + D = 20
=> D = 17
Therefore C + M + D = 7 + 3 + 17 = 27KG
Answer:
1410
Step-by-step explanation:
-6 times 5 is -30
47 times -30 is -1410
<h3>
Answer: B) Median</h3>
The middle vertical line inside the box is the median or the value of Q2. The term "median" is used more often instead of Q2, but your book may use this terminology as well.
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side notes:
* The left and right edges of the box are Q1 and Q3 respectively
* The IQR (interquartile range) is found by subtracting Q3 and Q1
* The min and max are the left and right most edges of the the whiskers, this is assuming there are no outliers
* There is no way to get the mean or mode from a box and whisker plot alone.
* The term "average" is too vague and could refer to mean, median, or mode.
