Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC =
≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
=
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA =
, then
∠ A =
(
) ≈ 66.9°
Answer:
Step-by-step explanation:
We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner
for Jayden we are given

This looks to be a line. The y values are each separated by a common difference
We can use two points to describe the line

Now we can set both
and
equal to 200


Keiko's blog will reach 200 subscribers fastest.
Answer:
<h2>N = 68°</h2>
Step-by-step explanation:
Since ∆LMM is a triangle all it's interior angles sum up to 180°
To find M add up all the angles and N and equate it to 180° to find N
That's
L + M + N = 180
33 + N + 79 = 180
N + 112 = 180
N = 180 - 112
We have the final answer as
<h3>N = 68°</h3>
Hope this helps you
Can you show the whole question?
The easiest method to solve problems like this is to graph the inequalities given and shade the regions that make them true. When you have properly shaded all of the regions, you will find that you have a region which is bounded on all four sides by one of the inequalities, and then you can find the x and y values which correspond to the vertices of the shaded region.
You didn't provide a function that you are trying to maximize in this example, but the idea is that you take all of the (x,y) points which correspond to the vertices and plug them into your objective function. The one which produces the largest value maximizes it (it is a similar process for minimizing it, but you'd be looking for the smallest value). Let me know if you need more help than that, or would like me to work out the example you have provided (I will need an objective function for it though).