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OLEGan [10]
3 years ago
15

Help! Pls! I’ll mark you as top

Mathematics
1 answer:
inysia [295]3 years ago
7 0
10 1/2x +2

- because you would add all the side lengths, so 2x+2x+ 3 1/4x+ 13 1/4x 1. You can combine like terms it to 10 1/2x+ 2.
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11/12 - 3/4 in simplest form​
VladimirAG [237]

Answer:

1/6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve for y.
k0ka [10]

Answer:

y = \frac{2}{9}

Step-by-step explanation:

multiply \frac{2}{3} by \frac{3}{3} to get \frac{6}{9}:

\frac{6}{9} + y - \frac{1}{9} = \frac{7}{9}

simplify:

y + \frac{5}{9} = \frac{7}{9}

subract \frac{5}{9} from both sides:

y = \frac{2}{9}

3 0
3 years ago
9a + 18c. What is the value of the expression when a = −5 and c = −1?
saw5 [17]
1. plug in the numbers for the variables, like this: 9(-5)+18(-1)

2. solve
Hopefully this helps! Let me know if you need more explanation.
4 0
3 years ago
Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea
Ulleksa [173]

Answer:

63 degrees

Step-by-step explanation:

add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.

3 0
3 years ago
Do alto de um farol cuja altura é de 20 m avista se um navio sob ângulo de depressão de 30°. A que distância , aproximadamente,
Mkey [24]
Esta é a trigonometria . Se você desenhar uma linha a partir do topo da casa de luz para o barco, você terá a hypotonuse de um triângulo. Um truque é lembrar que este é um triângulo especial. É um triângulo 30-60-90 , que tem propriedades especiais mostradas na fixação abaixo . por isso sabemos que o lado adjacente que não é o hyposonuse é x√3 . Agora sabemos que x<span>√3 = 20
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>










7 0
4 years ago
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