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3 years ago

Help! Pls! I’ll mark you as top

Mathematics

1 answer:

inysia [295]3 years ago

7 0

10 1/2x +2

- because you would add all the side lengths, so 2x+2x+ 3 1/4x+ 13 1/4x 1. You can combine like terms it to 10 1/2x+ 2.

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A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

Anton [14]

Answer: Y= -3/4x+13

Step-by-step explanation:

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

This is what i get

Slope of a line Y= mx+b

Y= 7

X= 8

M= -3/4

7= -3/4(8)+b

7= -6+b

7+6=b

13=b

Y= -3/4x+13

6 0

3 years ago

How to evaluate 11+y

s344n2d4d5 [400]

Good morning ☕️

Step-by-step explanation:

11+y is an expression that contains a variable ‘y’

then its value depends on ’y’

examples :

if y = 0 → 11+y = 11+0 = 11

if y = 1 → 11+y = 11+1 = 12

if y = 2 → 11+y = 11+2 = 13

and so on.

7 0

3 years ago

A hotel with 95 room has 65 for doubles and 25 for singles. Singles can be booked in any room, but reservations for two or more

kotykmax [81]

Answer: Y is less than or equal to 65 and X + y= less than or equal to 95

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=7%20%7Bx%7D%5E%7B3%7D%20%20%2B%204x%20-%205%20%2B%208%20%7Bx%7D%5E%7B5%7D%20" id="TexFormula1"

elixir [45]

Answer:

Step-by-step explanation:

The degree of a polynomial is determined by the largest exponent of a term within the polynomial.

Given

7x³ + 4x - 5 + 8 $x^{5}$

The term with the largest exponent is 8 $x^{5}$ with exponent 5

Thus the polynomial is of degree 5 → D

3 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago