Answer:
∠RPQ = 27
Step-by-step explanation:
In ΔSRQ,
∠R = 90
∠SQR = 36°
∠R + ∠SQR + ∠RSQ = 180 {Angle sum property of triangle}
90 + 36 + ∠RSQ = 180
126 + ∠RSQ = 180
∠RSQ = 180 - 126
∠RSQ = 54°
∠PSQ +∠RSQ = 180 {Linear pair}
∠PSQ + 54 = 180
∠PSQ = 180 - 54
∠PSQ = 126
In ΔPSQ,
SQ = PS ,
So, ∠SQP = ∠SPQ {Angles opposite to equal sides are equal}
∠SQP = ∠SPQ =x
∠PSQ + x +x = 180 {Angle sum property of triangle}
126 + 2x = 180
2x = 180 - 126
2x = 54
x = 54/2
x = 27
∠RPQ = 27°
Answer: its B because it does not pass the vertical line test
Answer:
(9, -5)
Step-by-step explanation:
The vector AC has coordinates (27, -18), because:
21 - (-6) = 27
-13 - 5 = -18
If the ratio of AB to BC is 5 to 4, it means that
AB = [5/(5+4)]AC = (5/9)AC
Therefore, we have
AB = (5/9)AC = (5/9) (27, -18) = (15, -10)
Which means that:
xB - xA = 15 <=> xB - (-6) = 15 <=> xB + 6 = 15 <=> xB = 9
yB - yA = -10 <=> yB - 5 = -10 <=> yB = -10 + 5 <=> yB = -5
So B has coordinates (9, -5).
Answer:
c. 412.5 cm^2
Step-by-step explanation:
first triangle: 5 x 15 = 75
75/2 = 37.5
rectangle: 15 x 19 = 285
triangle 2: 15 x 12 = 180
180/2 = 90
37.5 + 285 + 90 = 412.5
Answer:
V(x,y,z) ≈ 61.2 in
Step-by-step explanation:
for the function f
f(X)=x³
then the volume will be
V(x,y,z)= f(X+h) - f(X) , where h= 0.2 (thickness)
doing a Taylor series approximation to f(x+h) from f(x)
f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!
that can be approximated through the first term and second
f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2
since x=L=10 in (cube)
f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)
then
f(X+h) - f(X) ≈ 3*L*h*(h+L) = 3* 10 in * 0.2 in * ( 0.2 in + 10 in ) = 61.2 in
then
V(x,y,z) ≈ 61.2 in
V real = (10.2 in)³-(10 in)³ = 61 in
