<span>g(x) = x3
– x2 – 4x + 4 </span>
<span>You can find
the zeroes by factoring the equation. x<span>2 </span>(x - 1) - 4(x - 1) = 0 </span>
<span>(x2
- 4) (x - 1) = 0 </span>
(x + 2) (x -
2) (x - 1) = 0
x = 2, -2,
and 1
The
following are the key features of g(x):
g'(x) yields
the slope
g''(x) yields
the concavity
g'(x) = 0 provides
the critical points
<span>g''(x) = 0 provides the point of inflection</span>
Answer:
No
Step-by-step explanation:
The answer is no because no pocket can be empty and there isn't enough money to satisfy the condition. At least, one dollar must be stored in each pocket but the number (integer) of dollars in each pocket is different.
Let's store the minimum amount of dollars in the pockets while satisfying the condition. Place 1 dollar in the first pocket. The second pocket must have 2 dollars (it can't be 1 dollar, it must be a different number of dollars). The third pocket must have third dollars.
Repeating this process, the ninth pocket must have 9 dollars. At this moment, we have arranged 1+2+3+4+5+6+7+8+9=45 dollars in our pockets. But we only had 44 dollars! Plus, the tenth pocket is still empty.
If you store more dollars on the first, second, nth pockets, you will just run out of money more quickly than in our process above. so it's impossible to arrange the money in such way.
Answer:
1/9
Step-by-step explanation:
120/1080 can be simplified to 1/9
No regrouping: 4.34 + 4.35
Regrouping (carrying): 4.93 + 3.76
Answer:
A. -12 meters
B. 28 meters
C. 40 meters
Step-by-step explanation:
The surface of the ocean would be 0.
Taking this into account, 12 meters below would be 0 - 12, which is -12. Therefore A's elevation would be -12.
For the sea bird, 28 meters above the surface, which is again 0, would be 0 + 28. B's elevation is 28.
Since the fish is 12 meters below the surface and the sea bird is 28 meters above the surface, simply add the two numbers up to get a total of 40 meters. C would be 40 meters.
