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4 years ago

Which scenario describes a systematic error?

Physics

1 answer:

viktelen [127]4 years ago

4 0

A storm because nobody can control it.

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An electron is moving through a magnetic field whose magnitude is 9.21 × 10^-4 T. The electron experiences only a magnetic force

Marysya12 [62]

Answer:

$\theta=10.60^{\circ}$

Explanation:

Given that,

Magnetic field, $B=9.21\times 10^{-4}\ T$

Acceleration of the electron, $a=2.3\times 10^{14}\ m/s^2$

Speed of electron, $v=7.69\times 10^{6}\ m/s$

The force due to this acceleration is balanced by the magnetic force as :

$ma=qvB\ sin\theta$

$sin\theta=\dfrac{ma}{qvB}$

$sin\theta=\dfrac{9.1\times 10^{-31}\times 2.3\times 10^{14}}{1.6\times 10^{-19}\times 7.69\times 10^{6}\times 9.21\times 10^{-4}}$

$\theta=10.60^{\circ}$

So, the angle between the electron's velocity and the magnetic field is 10.6 degrees. Hence, this is the required solution,

8 0

4 years ago

Explain the process of a nuclear fusion reaction using hydrogen. Include the particles that are used to start and maintain the c

Zielflug [23.3K]

Answer it might be this

Explanation:

8 0

3 years ago

If 51.9 C of charge are transferred in a specific lightning strike and the potential difference is ∆V = 10.93 MV, how much energ

MA_775_DIABLO [31]

Quantity of charge unloaded = 51.9 Coulombs

Potential difference = 10.93 megavolts = 1.093 x 10⁷ volts

1 volt = 1 joule per coulomb

1.093 x 10⁷ volts = 1.093 x 10⁷ joules per coulomb

Energy = (1.093 x 10⁷ J/C) x (51.9 C)

Energy = 567.267 megaJoules

That's <em>5.67 x 10⁸ Joules</em> .

==> My wife's blow-dryer is marked 1260 watts.

If the energy in this lightning strike could be collected, bottled, stored, and used as needed, it could run my wife's blow-dryer for 125 hours. That would save us more than $30 on our electric bill !

8 0

3 years ago

A tall cylinder with a cross-sectional area 13.0 cm2 is partially filled with mercury; the surface of the mercury is 6.00 cm abo

kvv77 [185]

Answer:

V = 1060.8 cm³

Explanation:

we know that the pressure,

P = density x gravity x depth

ρm is the density of mercury

ρw is the density of water

the pressure due to mercury P₁= (ρm) g h₁

the pressure due to water P₂ = (ρw) g h₂

the total pressure

P = P₁ + P₂

P = (ρm) g h₁ + (ρw) g h₂

but the total pressure is double the pressure due to mercury.

(ρm) g h₁ =(ρw) g h₂

$h_2 = \dfrac{\rho_m\times h_1}{\rho_w}$

$h_2 =13.6\times 6$

h₂ = 81.6 cm

the height of the water is 81.6 cm

the volume

V = height x area

V = 81.6 x 13

V = 1060.8 cm³

the volume of water must be added to double the gauge pressure is V = 1060.8 cm³

8 0

3 years ago

A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s2. What is the mass of the box?

-BARSIC- [3]

Force = Mass x Acceleration
This is Newton's Second Law of Motion

Anyway,
450 = M x 15
450/15 = M
30kg = M

4 0

4 years ago