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Elina [12.6K]
3 years ago
14

_______is the resistance to motion offered by an object sliding over a surface

Physics
1 answer:
anyanavicka [17]3 years ago
5 0

friction is the force that resists the sliding or rolling of an object over another.

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What’s the answer ?????
Mice21 [21]

Answer:

<h2>Refer the attachment for answer and explanation please</h2>

Explanation:

This might surely help you ☺️❤️

7 0
3 years ago
If the<br> refractive index of benzere is 2.419,<br> what is the speed of light in benzene?
Grace [21]

Answer:

v=1.24\times 10^8\ m/s

Explanation:

Given that,

The refractive index of benzene is 2.419

We need to find the speed of light in benzene. The ratio of speed of light in vacuum to the speed of light in the medium equals the refractive index. So,

n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{2.419}\\\\v=1.24\times 10^8\ m/s

So, the speed of light in bezene is 1.24\times 10^8\ m/s.

4 0
3 years ago
Two trains are moving at 30 m/s in opposite directions on the same track. The engineers see simultaneously that they are on a co
stellarik [79]

Answer:

Acceleration of train needed to avoid collision = -0.9 m/s²

Explanation:

Here both trains are similar with 1000 m apart with same speed.

So one train has to move 500 m before stopping just to avoid collision.

We have

Initial velocity, u =  30 m/s

Acceleration , a = ?

Displacement, s = 500 m

Final velocity, v = 0 m/s

We have equation of motion v²= u² + 2as

Substituting

     v²= u² + 2as

     0²= 30² + 2 x a x 500

    a = -0.9 m/s²

Acceleration of train needed to avoid collision = -0.9 m/s²

8 0
3 years ago
a machine is used to lift crates of oranges has an efficiency of 65%. if the machine provides 1300 newtons through a distance of
mylen [45]

Given data

  efficiency (η) = 65 %

                        = 0.65

  Machine provides (Work done by the machine) = 1300 × 50

                                                                                 = 65000 J

  efficiency (η) = work done by the machine ÷ work supplied to the machine

               0.65 =  65000 ÷ Input work

              Input work = 100000 J

                                = 100 KJ

5 0
3 years ago
If the labor force of 155 million people is growing by 1.0 percent per year, how many new jobs have to be created each month to
dybincka [34]

First let us compute for the total growth in population.

Growth = 155 million * 0.01

Growth = 1.55 million

 

Since there are 12 months in a year, therefore the new jobs every month should be:

new jobs per month = 1.55 million / 12

<span>new jobs per month = 0.129 million = 129,167 </span>

8 0
4 years ago
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