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Mumz [18]
2 years ago
10

A horse is galloping for 15 minutes and runs a distance of 5 miles. How many minutes would it take the horse to run 23 miles?

Mathematics
1 answer:
Blababa [14]2 years ago
5 0

Answer:

A runner ran 20 miles in 150 minutes. If she runs at that speed,

Step-by-step explanation:

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Solve the system of equations below by graphing.
AleksandrR [38]
I think it would be B hope it helps
5 0
3 years ago
Read 2 more answers
Add -13/4+2/5 using the number line. select the location on the number line to plot the sum
Ivahew [28]
The answer is if you convert. we cant see the number line so, we cant tell you the second part of the problem.. attach the image please.

ok so convert.. -13/4 becomes -65/20 and 2/5 becomes 8/20, so add that and get -57/20, then simplify how you want to. thats your answer
4 0
3 years ago
1. When a cannonball is fired, the equation of its pathway can be modeled by h = -1612 + 128t.
sashaice [31]

Answer:

The maximum height of the ball is 256m

Step-by-step explanation:

Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t

At maximum height, the velocity of the ball is zero.

velocity = dh/dt

velocity = -32t + 128

Since v = 0 at maximum height

0 = -32t+128

32t = 128

t = 128/32

t = 4seconds

The maximum height can be gotten by substituting t = 4 into the modelled equation.

h = -16t² + 128t

h = -16(4)²+128(4)

h = -16(16)+512

h = -256+512

h = 256m

4 0
3 years ago
An airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. if her speed is 200 m/s at
yulyashka [42]
Centripetal acceleration is given by:
g=v^2/r
where:
v=velocity
r=rate
But
V=200 m/s, g=9.8 m/s^2
plugging the values in the formula we obtain:
9.8=200^2/r
r=200^2/9.8
r=4081.63 m
5 0
3 years ago
What is 4(-8x+5)=-32x26
Ksivusya [100]

Answer:

x = -25.375

Step-by-step explanation:

4(-8x+5) = -32 x 26

-32x + 20 = 832

-32 = 812

x = -25.375

6 0
3 years ago
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