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Mumz [18]
3 years ago
10

A horse is galloping for 15 minutes and runs a distance of 5 miles. How many minutes would it take the horse to run 23 miles?

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

Answer:

A runner ran 20 miles in 150 minutes. If she runs at that speed,

Step-by-step explanation:

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If log(16)=s, what is the value of 2/3 log(6400) - 1/3 log(1600) in terms of s?
eduard

The value of   \dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)  in terms of s will be

\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)

<h3>What is Logrithm?</h3>

A quantity representing the power to which a fixed number (the base) must be raised to produce a given number.

Here we have the expression:-

\dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)

So in terms of s the expression will become:-

\dfrac{2}{3}(400s)-\dfrac{1}{3}(1000s)

To know more about logarithm follow

brainly.com/question/25710806

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8 0
2 years ago
Which is the best to buy?
g100num [7]
The answer is D........
5 0
3 years ago
Write the slope-intercept form of the equation of the line through the given points:
vredina [299]

Answer:

equation of line

x-2y=8

Step-by-step explanation:

equation of line in slope intercept form

(y-y1)={(y2-y1)/(x2-x1)}(x-x1)

 or,(y+3)={(-5+3)/(-2-2)}(x-2)

 or,(y+3)=(1/2)(x-2)

  or,2y+6=x-2

   or,6+2    =x-2y  

or,x-2y=8

3 0
2 years ago
If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
Zinaida [17]

Answer:

Step-by-step explanation:

 This is a simple proportion problems.

7 kilogram weight attache to a spring stretches  = 6 meters

 1 kilogram would stretch                                       =  6/7 m

Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters

                                                                                 =  36 meters.

                                                                         

 

8 0
3 years ago
The model includes a new park in the center of the city. If the dimensions of the
11111nata11111 [884]

The question is incomplete. Here is the complete question.

As a part of city building refurbishment project,  architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.

The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?

Answer: 81 feet by 153 feet

Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.

In the refurbishment project, the unit scale is given by

1 inch = 9 feet

So, the dimensions of the new park in actual dimensions would be

1 inch = 9 feet

9 inches = x

x = 9.9

x = 81 feet

1 inch = 9 feet

17 inches = y

y = 17.9

y = 153 feet

The actual dimensions of the new park are 81 feet by 153 feet.

6 0
3 years ago
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