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2 years ago

13

Archie earns $6 each week for doing his chores. He puts all but $2 into a savings account. How much money will Archie save in 2

months if there are 4 weeks in each month?

2 answers:

Virty [35]2 years ago

6 0

Answer:

$16

Step-by-step explanation: 2 * 4=8+8=16

Lynna [10]2 years ago

6 0

Answer: in 8 weeks he will save $32

Step-by-step explanation: there are 8 weeks in 2 months so he will save $4 per week multiplied by 8 weeks

So 4*8 =$32

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Really easy points!!!!!! Please solve for all three answers.

katen-ka-za [31]

Answer:

1/64, 1/256, 1/1024

Step-by-step explanation:

To get from 16 to 4 we multiply by 1/4

To get from 4 to 1 we multiply by 1/4

Each time we multiply by 1/4

The next term would be 1/16 * 1/4

1/16 * 1/4 = 1/64

The take that term 1/64 and multiply by 1/4

1/64*1/4 = 1/256

Finally take 1/256 and multiply by 1/4

1/256*1/4 =1/1024

8 0

3 years ago

What is 2x+1<8x-2 I dont get it please help

rjkz [21]

Answer: x> 1/2

Step-by-step explanation:

if 2x+1∠ 8x-2

inequality , treat this problem like any other equation

have the unknown(x) in one side, and the values on the other side

2x-8x < -1-2

-6x< -3 we multiply by -1, do not forget if we multiply by -1 the sign will change

6x>3 divide by 3

2x>1

x>1/2

6 0

2 years ago

Cindy's job is to check computer printers for defects. Out of 420 printers she has to check, only 3 of the first 84 have been de

kaheart [24]

46% printers are defective = 106 printers defective

5 0

3 years ago

As a first step in solving the system shown, Yumiko multiplies both sides of the equation 2x – 3y = 12 by 6. By what factor shou

GenaCL600 [577]

Answer:

Yumiko should multiply the other equation by 3.

If she adds the two equations she would be left with the variable 'x'.

Step-by-step explanation:

Given the two equations are as follows:

$2x - 3y = 12 \hspace{5mm} \hdots (1)$

$5x + 6y = 18 \hspace{5mm} \hdots (2)$

It is given that she multiplies the first equation by 6. Therefore, (1) becomes

$12x - 18y = 72 \hspace{15mm} \hdots (a)$

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.

The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.

Therefore, Equation (2) becomes:

$15x + 18y = 54 \hspace{5mm} \hdots (b)$

Now, we add Equation (a) and Equation (b).

$\implies 12x - 18y + 15x + 18y = 72 + 54$

$\implies 27x = 126$

Factor: 3

Equation: 27x = 126

7 0

2 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago