Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer:
x = 7
Step-by-step explanation:
simplify 16/32
16/32 divided by 8/8=2/4
2/4 divided by 2=1/2
so
1/2 = x/14
to get to 14 from 2 you need to multiply by 7
1/2 times 2/2 = 7/14
so x = 7
Answer:
the answer is 58 your welcome
Answer:
idk
Step-by-step explanation:
sorry i needed the points sorry
P = A / (1 + rt)
P = 80000 / (1 + (0.09)(0.5))
P = <span>$ 76,555.02</span>