Answer:
The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Z-table as such z has a p-value of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?
A sample of n is needed, and n is found when M = 4. So






The minimum sample size needed is
. If n is a decimal number, it is rounded up to the next integer.
is the standard deviation of the population.
6.4 - 2x - 6.63x = 610.5
subtract 6.4 from both sides
-2x -6.63x =604.1
collect like terms
-8.63x = 604.1
divide both sides by -8.63
x= -70
27; The first stack is 3 x 3 (= 9). You then multiply 9 by 3 (for each of the 3 stacks). Basically, 3 x 3 x 3.
Answer:
I think the answer is x is 16 and y is 20? I could be wrong tho
Step-by-step explanation:
First, subtract -7 from -1 to get 8.
Then, add the 12 and you get 16 for x.
First, subtract 7y from 9x to get 2y
Then, add 4 to get 20 for y.
It's 100
Because You multiply the sample proportion to 2000