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abruzzese [7]
3 years ago
5

Help so hard!!! i need help

Mathematics
2 answers:
aleksklad [387]3 years ago
3 0

Answer:

1. b

2. are like terms

Step-by-step explanation:

1. this is b because when you distribute, each of the terms in the parentheses will get multiplied by 3.

2. these are like terms because they have no variables. they are just numbers so they are like terms

Kay [80]3 years ago
3 0
The answer is B make sure you use the distribute property
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At a restaurant the ratio of kids meals sold to adult meals was 8 to 5 if there were 72 kids meals sold how many adult meals wer
docker41 [41]

Answer:

45

Step-by-step explanation:

There were 72 kids meals sold which is represented by 8 parts of the ratio.

Divide by 8 to find the value of one part of the ratio

72 ÷ 8 = 9 ← value of 1 part of the ratio, thus

5 × 9 = 45 ← number of adult meals sold

6 0
4 years ago
Read 2 more answers
What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x? (1 point)
vodka [1.7K]

f(x) = x³ - 2x² - 24x

x³ - 2x² - 24x = 0

x(x² - 2x - 24) = 0

x = 0

x² - 2x - 24 = 0

a = 1, b = -2, c = -24

Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100

x = (-(-2) - 10)/(2 * 1) = -8/2 = -4

x = (-(-2) + 10)/(2 * 1) = 12/2 = 6

Answer: 2)

5 0
3 years ago
Students in a representative sample of 69 second-year students selected from a large university in England participated in a stu
Serhud [2]

Answer:

95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

Step-by-step explanation:

We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

                         P.Q. = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean procrastination score = 41

             s = sample standard deviation = 6.89

            n = sample of students = 69

            \mu =  population mean estimate

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.</em>

So, 95% confidence interval for the true mean, \mu is ;

P(-1.9973 < t_6_8 < 1.9973) = 0.95  {As the critical value of t at 68 degree

                                        of freedom are -1.9973 & 1.9973 with P = 2.5%}  

P(-1.9973 < \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } } < 1.9973) = 0.95

P( -1.9973 \times{\frac{s}{\sqrt{n} } } < {\bar X -\mu} < 1.9973 \times{\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.9973 \times{\frac{s}{\sqrt{n} } } < \mu < \bar X+1.9973 \times{\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for </u>\mu =[\bar X-1.9973 \times{\frac{s}{\sqrt{n} } } , \bar X+1.9973 \times{\frac{s}{\sqrt{n} } }]

                              = [ 41-1.9973 \times{\frac{6.89}{\sqrt{69} } } , 41+1.9973 \times{\frac{6.89}{\sqrt{69} } } ]

                              = [39.34 , 42.66]

Therefore, 95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

5 0
3 years ago
Win bakes fruit bars in a pan shaped like a rectangular prism. The volume of the pan is 120 cubic inches. The length of the pan
Svetllana [295]

Answer:

24 inches

absolutely 100% definitely

8 0
2 years ago
Question 19 What must be done to the graph of f(x) = |x| to obtain the graph of the function g(x) = 3/7 |x+4|-10?
Sergio [31]

Answer:

The graph of f is shifted left 4 units, vertically shrunk by a factor of \frac{3}{7} and shifted down 10 units.

Step-by-step explanation:

The base graph is f(x)=|x|

The transformed graph is g(x)=\frac{3}{7}|x+4|-10

Let us rewrite g(x) in terms of f(x) to get:

g(x)=\frac{3}{7}f(x+4)-10

This means that f(x) was vertically shrunk by a factor of \frac{3}{7} and shifted  4 units to the left and 10 units down.

5 0
4 years ago
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