Question

The sum of Rhonda and her daughter Tenica’s age is 64. The difference in their ages is 28. How old is each person?

Answer 1

Answer:

The mother (Rhoda) is 46 years old.

The daughter (Tenica) is 18 years old

Step-by-step explanation:

Let the age of the mother (Rhoda) be m

Let the age of the daughter (Tenica) be d.

The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:

m + d = 64 ... (1)

The difference in their ages is 28. This can be written as:

m – d = 28 ... (2)

From the above illustrations, the equation obtained are:

m + d = 64 ... (1)

m – d = 28 ... (2)

Solving by elimination method:

Add equation 1 and 2 together

. m + d = 64

+ m – d = 28

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

2m = 92

Divide both side by 2

m = 92/2

m = 46

Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1

m + d = 64

m = 46

46 + d = 64

Collect like terms

d = 64 – 46

d = 18

Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.