The garden has a 4m length and a 2m width. The perimeter of any given rectangle is two times the sum of the length and the width of the same rectangle.

Perimeter = 2 × (length of the rectange + width of the rectangle)

Perimeter = 2 × (4m + 2m) = 2 × (6m) = 12 meters.

So the gardens perimeter is equal to 12 meters.
Ramond needs to buy a fence for a garden whose parameter is 12 meters.

3 0

3 years ago

Ray opened a savings account with $600 at 4.5% interest compounded quarterly and kept it in the account for 2 years. How much wa

nadezda [96]

Answer:

600(1 +0.045/4)^8

Step-by-step explanation:

8 0

2 years ago

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PLEASE HELP ASAP!!!!

OleMash [197]

Answer:

y = -2x + 8

Step-by-step explanation:

The point slope form of an equation is written as

y = mx + c ...............(i)

Where m is the slope and c is the constant

Now we Know that the equation is

y + 2 = -2(x-5)

and the given points are

m= -2

x = 5

and y= -2

Putting these values in equation (i) to find the value of c

y = mx + c

it becomes

-2 = -2(5) + c

-2 = -10 + c

Adding 10 on both sides

-2 + 10 = -10 + 10 + c

8 = c

or c=8

Now we have the values of m and c

where m= -2 and c = 8

Point slope form of an equation is

y = mx + c

putting the values of m and c to get equation in slope intercept form is

y = (-2)x + 8

y = -2x + 8

Other method:

The given point slope form is

y + 2 = -2(x-5)

We have to change it in y= mx + c form

so solving it

y + 2 = -2x + 10

Subtracting 2 from both sides

y + 2 -2 = -2x + 10 -2

y = -2x + 8

which is same is

y=mx + c

so the required equation is

y = -2x + 8

7 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

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