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2 years ago

andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all

Mathematics

2 answers:

Whitepunk [10]2 years ago

8 0

$\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}$

1 bunch of balloons contain 6 balloons

$\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}$

Number of balloons in 4 bunches = ?

$\large\underline{\underline{\maltese{\purple{\pmb{\sf{\: Solution :-}}}}}}$

To find the number of balloons in 4 bunches we need to multiply the bumber of balloons in 1 bunch by the number of bunches.

$\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches$

$\sf \nrightarrow \: 6 \times 4 = 24$

➪ Thus, There are 24 balloons in 4 bunches...~

kow [346]2 years ago

3 0

No of balloons in each bunches=4
Total bunches=6

Now

Total balloons =Total bunches×Balloons in each bunch.

Total balloons:-

$\\ \rm\Rrightarrow 6(4)$

$\\ \rm\Rrightarrow 24$

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3 years ago

A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

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Hence, the area of the mat is 246 in².

6 0

3 years ago

Please help and NO LINKS!

Zielflug [23.3K]

Answer:

2/100 is the answer to the question

8 0

3 years ago

Read 2 more answers

I need help with this question pls help

Blababa [14]

Answer:

y = - 4

Step-by-step explanation:

x = - 2

3x - 2y = 2

substitute x = - 2 into 3x - 2y = 2

3(- 2) - 2y = 2 ← step 1

- 6 - 2y = 2 ( add 6 to both sides ) ← step 2

- 2y = 8 ( divide both sides by - 2 )

y = - 4

5 0

2 years ago

A randomly selected sample of n =51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years. Calc

Aloiza [94]

Answer:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

Step-by-step explanation:

Information given

$\bar X= 59$ represent the sample mean

$s= 10$ represent the sample deviation

$n= 51$ represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=51-1=50$

The Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.01$ ,and the critical value would be $t_{\alpha/2}=2.40$

And replacing we got:

$59-2.40\frac{10}{\sqrt{51}}=55.639$

$59+ 2.40\frac{10}{\sqrt{51}}=62.361$

The 98% confidence interval would be given by (55.639;62.361)

3 0

3 years ago