Hello!
**Process pictured below**
When dividing, find how many times the first time in the divisor (2x + 3) fits into the first time of the dividend (2x³ + 5x² - 3x - 5). In this step, it fits x² times.
Multiply x² by the terms in the divisor and subtract from the dividend. Bring down the next term in the dividend to continue the process.
Repeat this step until you reach the last number. In this case, there was a remainder of 4. In order to write the remainder, you must express it over the divisor which makes it 4 / 2x + 3.
Please ensure that you've copied down this problem correctly. You speak of someone named "Yarin" but also speak of "my" and "I". Are there really two different people who "star" in this problem? Are you studying "ratios" right now?
9 x 4 = 12 this the answer
The solution of the system of equation is the intersection point of the two quadratic equations, so we need to equate both equations, that is,
So, by moving the term -3x^3+20 to the left hand side, we have
Then, in order to solve this equation, we can apply the quadratic formula
In our case, a=5, b=-3 and c=-30. So we get
which gives
By substituting these points into one of the functions, we have
and
Then, by rounding these numbers to the nearest tenth, we have the following points:
Therefore, the answer is the last option
21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
