Answer:
(0.102, -0.062)
Step-by-step explanation:
sample size in 2018 = n1 = 216
sample size in 2017 = n2 = 200
number of people who went for another degree in 2018 = x1 = 54
number of people who went for another degree in 2017 = x2 = 46
p1 = x1/n1 = 0.25
p2 = x2/n2 = 0.23
At 95% confidence level, z critical = 1.96
now we have to solve for the confidence interval =
<h2>
</h2>
= 0.02 ± 1.96 * 0.042
= 0.02 + 0.082 = <u>0.102</u>
= 0.02 - 0.082 = <u>-0.062</u>
<u>There is 95% confidence that there is a difference that lies between - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.</u>
<u></u>
<u>There is no significant difference between the two.</u>
Answer:
y=1/3x+4
Step-by-step explanation:
To simplify 7C4 we use the combination formula given by:
nCr=n!/[(n-r)!r!]
thus:
In our case we shall have:
n=7 and r=4
7C4
=7!/[(7-4)!4!]
=5040/[6×24]
=5040/144
=35
The answer is 35
Answer:e=-10
Step-by-step explanation:
-2e-7=13
-2e=20
e=-10
Answer:
0 ≤ c ≤ 12
Step-by-step explanation:
The function can be rearranged to ...
p = 200c(12 -c) -4700
suggesting that revenue will be zero for a charge of 0 or for a charge of 12, and that fixed expenses are 4700. Charges less than 0 are uninteresting, and charges high enough to cause the number of customers to be negative also don't make any sense in this context.
Though out of the range of likely consideration, charges low or high enough to cause profit to be negative (more than 9.54, for example) seemingly can be reasonably modeled by this function.
