Lizz's dog is 10 1/2 years old pages dog is 18 months old how much older is lizzy's dog
1 answer:
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Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
The answer to your question is below
Step-by-step explanation:
2. Just find the prime factors of 128 and simplify
3.- Get the square roots and simplify
3i + 4i
7i
4.- None of the choices is equal to one, because the exponents are pair.
5.- 1/3x² + 10 = 7
1/3x² = 7 - 10
1/3x² = -3
x² = -3(3)
x² = -9
x = ±3i