Answer:
40 cm.
Step-by-step explanation:
Given,
height of the object = 10 cm
Distance of the object from the X-ray= 50 cm
Distance of detector from the source = 2 m = 200 cm
Height of the image, h = ?
Now,
Again applying
h = 40 cm
Hence, height of the image is equal to 40 cm.
Answer:
(-8 , 3)
Step-by-step explanation:
(x1 , y1) (x2 , y2) = (-10 , -1) (-6 , 7)
,
-6 is going to be my x1 and -10 my y1
7 is going to be my x2 and -1 my y2
(-8 , 3)
By running in a bearing of 127°, Paul motion is in the south eastern direction.
Correct responses:
a. Please find attached the required diagram created with MS Visio
b. Paul's distance travelled east is approximately 11.98 km
Given:
The distance Paul runs = 1.5 km
The bearing Paul is running = 127°
a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction
Please find attached the diagram representing the situation, created with MS Visio.
b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;
Pau's distance travelled in the south direction relative to the starting point
is given by the vertical distance travelled relative to the x-axis, which is
given as follows;
Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>
Learn more about bearings in trigonometry here:
