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Table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
<h3>What is a parabola?</h3>It is defined as the graph of a quadratic function that has something bowl-shaped.
We have the tables shown in the picture.
We know the quadratic form of a parabola is:
y = ax² + bx + c
If a > 0 the parabola opens
In the equation:
y = x² - 6x
1 > 0 the parabola opens and y-intercept is:
y = 0 (plug x = 0 in the given equation)
a = 1, b = -6, and c = 0
Thus, table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
Learn more about the parabola here:
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Answer:
No, the manager is not correct based on the 95% confidence interval.
Step-by-step explanation:
We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .
The Pivotal quantity for 95% confidence interval is given by;
~
where, X bar = sample mean = $1080
s = sample standard deviation = $260
n = sample size = 35 {five-week}
So, 95% confidence interval for average daily revenue, is given by;
P(-2.032 < < 2.032) = 0.95
P(-2.032 < < 2.032) = 0.95
P(-2.032 * <
< 2.032 *
) = 0.95
P(X bar - 2.032 * <
< X bar + 2.032 *
) = 0.95
95% confidence interval for = [ X bar - 2.032 *
, X bar + 2.032 *
]
= [ 1080 - 2.032 * , 1080 + 2.032 *
]
= [ 990.70 , 1169.30 ]
<em>No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.</em>
Therefore, the store manager believe is not correct.