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shutvik [7]
3 years ago
6

PLAZ HURI AND ANSOR WORT 50 POITNZS AND MAOR IF U GET BRIANLEUSTSTS!!!! (Last one for today lul)

Mathematics
2 answers:
aleksley [76]3 years ago
5 0

I just took the quiz, the correct answer is

A. There is no relationship between the size of a school building and the number of students who play an instrument because the scatterplot does not have a cluster.


klemol [59]3 years ago
4 0
My best educated guess would be D.  
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Clear parenthesis and combine like terms.<br> −2( − 4) − 3( + 2)<br> Show all the work.
netineya [11]

Answer:

-(2-4)+(3+2)

Step-by-step explanation:

ah,,, those are my think

6 0
3 years ago
Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each
GarryVolchara [31]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each of the following.

(i)    3 to 4

(ii)    3 to 3.5

(iii)    3 to 3.1

(b) Find the instantaneous rate of change when r = 3.  A'(3)

Area of a circle A(r)= πr²

The average rate of change of the area of a circle with respect to its radius

ΔA(r)/Δr = πr₂²-πr₁²/r₂-r₁

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

i) If the radius changes from 3 to 4

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(4²-3²)/4-3

ΔA(r)/Δr = π(16-9)/1

ΔA(r)/Δr = 7π

<em>Hence, average rate of the area of a circle when the radius changes from 3 to 4 is 7π</em>

ii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.5²-3²)/3.5-3

ΔA(r)/Δr = π(12.25-9)/0.5

ΔA(r)/Δr = 3.25π/0.5

ΔA(r)/Δr = 6.5π

<em>Hence, average rate of the area of a circle when the radius changes from 3 to 3.5 is </em>6.5π

iii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.1²-3²)/3.1-3

ΔA(r)/Δr = π(9.61-9)/0.1

ΔA(r)/Δr = 0.61π/0.1

ΔA(r)/Δr = 6.1π

<em>Hence, average rate of the area of a circle when the radius changes from 3 to 3.1 is </em> 6.1π

iv) Instantaneous rate of change A'(r) = 2πr

When r = 3;

A'(3) = 2π(3)

A'(3) = 6π

<em>Hence, the instantaneous rate of change when r = 3 is 6π </em>

5 0
3 years ago
I don’t understand this problem
Paha777 [63]

Answer:

the pair of angles of SUR and NUR are complimentary so the measure of NUR  is 49 degrees. TUR is equivalent to RUQ

Step-by-step explanation:

Complimentary means they add up to 90 degrees. so 90-41= 49 so the angle measure of NUR is 90 degrees.

6 0
2 years ago
Read 2 more answers
10. Saul works two part-time jobs. Last week, he worked 14 hours at a shoe store, and 19
Sedbober [7]

Answer:

shoe store $7.80/hour

telemarketer: $6.90/hour

Step-by-step explanation:

Let s = hourly salary at the shoe store.

Let t = hourly salary as a telemarketer.

14s + 19t = 240.3

19s + 22t = 300

Multiply both sides of the first equation by 19. Multiply both sides of the second equation by -14. Then add them.

         266s + 361t = 4565.7

(+)     -266s - 308t = -4200

----------------------------------------

                       53t = 365.7

t = 6.9

Substitute 6.9 for t in the first equation and solve for s.

14s + 19(6.9) = 240.3

14s + 131.1 = 240.3

14s = 109.2

s = 7.8

Answer:

shoe store $7.80/hour

telemarketer: $6.90/hour

6 0
2 years ago
Place the following steps in order to describe how to solve the following equation:​​ 2(2x+3)-2=52(2x+3)−2=5
Alex_Xolod [135]

Answer:

frist parentheses then subtract

3 0
2 years ago
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