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3 years ago

PLEASE HELP ASAAAPPPPPP

Mathematics

1 answer:

Ad libitum [116K]3 years ago

7 0

A) 276 / 138 = 2

B) 26/2 = 13, 13/2 = 6.5

Answer is B

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Which of the following best describes the set of all numbers of the form a+bi where a and b are any real numbers and i equals sq

Andrei [34K]

<h3>Answer: B) Complex numbers</h3>

Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.

If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number

If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary

6 0

3 years ago

I really need help with this can somebody help me ?

Mama L [17]

<em>Answer</em>

a. Vertical shrink by a factor of 1/3

<em>Step-by-step explanation</em>

Function transformation

• a,f(x) vertically compresses f(x) when 0 < a < 1

Given the function:

$f(x)=x^2$

Multiplying f(x) by a = 1/3, we get:

$\frac{1}{3}f(x)=\frac{1}{3}x^2=h(x)$

Then, f(x) is vertically shrunk by a factor of 1/3

6 0

11 months ago

Travis had a rectangular garden that measured 10feet by 12 feet. He planted pumpkins in his garden. Each pumpkin olant took up 2

BartSMP [9]

dividing the length and width by 2

10 ÷ 2 = 5 and 12 ÷ 2 = 6

he can plant 5 × 6 = 30 pumpkin plants

8 0

3 years ago

Can someone answer part B for me? Thank you and will give brainliest.

frez [133]

Answer:

The answer to part B is B.

Step-by-step explanation:

Could you take another photo so I can see the bottom of the page?

4 0

3 years ago

Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B

Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,

B = event that the selected student has a MasterCard,

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0

2 years ago