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stepan [7]
3 years ago
13

Write an inequality for the graph.

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

y\geq |x-5|+1

Step-by-step explanation:

From the graph it is clear that it is a V-shaped curve. So, the given graph represents an absolute value function.

The vertex form of an absolute function is

y=|x-h|+k

where, (h,k) is vertex.

The vertex of the given graph is (5,1). So the related equation of the graph is

y=|x-5|+1

Related line is a solid line and shaded region lie above the line, So the sign of inequality must be ≥.

y\geq |x-5|+1

Check by (0,0).

0\geq |0-5|+1

0\geq 6

It is a false statement.

Therefore, y\geq |x-5|+1.

icang [17]3 years ago
7 0

Answer:

The answer to your question is:

The inqualites are       y > -x + 6    and    y > x - 4

Step-by-step explanation:

Data

Look for the equations of the lines

First line

A (5, 1)

B (0,6)

m = (6 - 1) /(0 - 5)

m = 5 / -5

m = -1

 y- y1 = m(x - x1)

y - 1 = -1(x - 5)

y -1 = -x + 5

y = -x + 5 + 1

 y = -x + 6    The shadow are is upward the line then

y > -x + 6

Second line

A (5, 1)

B (6, 2)

m = (2 - 1) / (6 - 5)

m = 1 / 1 = 1

y - 1 = 1(x - 5)

y = x - 5 + 1

y = x - 4   The shadow must be upward the line, then

y > x - 4

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2 years ago
In a basketball game, Team A defeated Team B with a score of 97 to 63. Team A won by scoring a combination of two-point baskets,
-BARSIC- [3]

Answer:

14 free throw baskets , 25 two point baskets and 11 three point baskets

Step-by-step explanation:

Let n₁ represent the number of free-throw baskets, n₂ represent the number of two point baskets and n₃ represent the number of three point baskets.

Now, from the question, the number of two point baskets, n₂ is greater than the free throw baskets by 11. This is written as n₂ = n₁ + 11. Also, the number of three point baskets n₃ is three less than the number of free point baskets. This is written as n₃ = n₂ - 3. Since our total number of points equals 97, it follows that, sum of number of points multiplied by each point equals 97. So, ∑(number of points × each point) = 97. Thus,

n₁ + 2n₂ + 3n₃ = 97. Substituting n₂ and n₃ from above, we have n₁ +2(n₁ + 11) + 3(n₁ - 3) = 97.

Expanding the brackets, we have, n₁ + 2n₁ + 22 + 3n₁ - 9 = 97

collecting like terms, we have 6n₁ + 13 = 97

6n₁ = 97 - 13

6n₁ = 84

dividing through by n₁ we have, n₁ = 84/6 =14

so n₁ our free throw baskets equals 14. Substituting this into n₂ our number of two point baskets equals n₂ = n₁ + 11 = 14 + 11 = 25. Our number of three point baskets n₃ = n₁ - 3. So, n₃ = 14 -3 = 11.

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Answer:

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Step-by-step explan

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