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stepan [7]
3 years ago
13

Write an inequality for the graph.

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

y\geq |x-5|+1

Step-by-step explanation:

From the graph it is clear that it is a V-shaped curve. So, the given graph represents an absolute value function.

The vertex form of an absolute function is

y=|x-h|+k

where, (h,k) is vertex.

The vertex of the given graph is (5,1). So the related equation of the graph is

y=|x-5|+1

Related line is a solid line and shaded region lie above the line, So the sign of inequality must be ≥.

y\geq |x-5|+1

Check by (0,0).

0\geq |0-5|+1

0\geq 6

It is a false statement.

Therefore, y\geq |x-5|+1.

icang [17]3 years ago
7 0

Answer:

The answer to your question is:

The inqualites are       y > -x + 6    and    y > x - 4

Step-by-step explanation:

Data

Look for the equations of the lines

First line

A (5, 1)

B (0,6)

m = (6 - 1) /(0 - 5)

m = 5 / -5

m = -1

 y- y1 = m(x - x1)

y - 1 = -1(x - 5)

y -1 = -x + 5

y = -x + 5 + 1

 y = -x + 6    The shadow are is upward the line then

y > -x + 6

Second line

A (5, 1)

B (6, 2)

m = (2 - 1) / (6 - 5)

m = 1 / 1 = 1

y - 1 = 1(x - 5)

y = x - 5 + 1

y = x - 4   The shadow must be upward the line, then

y > x - 4

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0.5,0.25,3/8,1 1/4

Step-by-step explanation:

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Help me solve for x. the angles they give to you are 138, 78, and 94. please help ​
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Answer:

x = 8

Step-by-step explanation:

180 = 78 + 94 + x

180 =172 + x

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18 = x

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De un grupo de 60 personas, la tercera parte finalizó la escuela primaria solamente, y las ⅖ partes completaron la secundaria. E
notka56 [123]

Answer:

36 personas

Step-by-step explanation:

las 2/5 partes q completaron secundaria tambien finalizaron primaria

con lo cual el tercio que estudio primaria esta dentro del grupo de personas que estudiaron

60*2/5 = 24  

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4 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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