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stepan [7]
3 years ago
13

Write an inequality for the graph.

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:

y\geq |x-5|+1

Step-by-step explanation:

From the graph it is clear that it is a V-shaped curve. So, the given graph represents an absolute value function.

The vertex form of an absolute function is

y=|x-h|+k

where, (h,k) is vertex.

The vertex of the given graph is (5,1). So the related equation of the graph is

y=|x-5|+1

Related line is a solid line and shaded region lie above the line, So the sign of inequality must be ≥.

y\geq |x-5|+1

Check by (0,0).

0\geq |0-5|+1

0\geq 6

It is a false statement.

Therefore, y\geq |x-5|+1.

icang [17]3 years ago
7 0

Answer:

The answer to your question is:

The inqualites are       y > -x + 6    and    y > x - 4

Step-by-step explanation:

Data

Look for the equations of the lines

First line

A (5, 1)

B (0,6)

m = (6 - 1) /(0 - 5)

m = 5 / -5

m = -1

 y- y1 = m(x - x1)

y - 1 = -1(x - 5)

y -1 = -x + 5

y = -x + 5 + 1

 y = -x + 6    The shadow are is upward the line then

y > -x + 6

Second line

A (5, 1)

B (6, 2)

m = (2 - 1) / (6 - 5)

m = 1 / 1 = 1

y - 1 = 1(x - 5)

y = x - 5 + 1

y = x - 4   The shadow must be upward the line, then

y > x - 4

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4vir4ik [10]

Answer:

A n B = {6}

Step-by-step explanation:

Given he sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3)

A = {2, 4, 6, 8}

B = {3, 6, 9, 12, 15...}

A n B includes the numbers are are common to both sets i.e number that we can find in both A and B.

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3 years ago
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statuscvo [17]

Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

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x = 561

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Total = 16
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Rounding off to 2 decimal places,
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