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pychu [463]
3 years ago
14

Write (3 - 3i)(1 - 6i) as a complex number in standard form

Mathematics
2 answers:
julia-pushkina [17]3 years ago
4 0

Answer:

-15 - 21i

Step-by-step explanation:

<u>Step 1:  FOIL</u>

(3 - 3i)(1 - 6i)

(3 * 1) + (3 * -6i) + (-3i * 1) + (-3i * -6i)

(3) + (-18i) + (-3i) + (18i^2)

3 - 18i - 3i - 18

-15 - 21i

Answer:  -15 - 21i

Maslowich3 years ago
4 0

Answer:

-15-2i

Step-by-step explanation:

(3-3i)(1-6i)

3-18i-3i+18i^2

3-2i-18

-15-2i

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