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jek_recluse [69]
2 years ago
9

A 6 sided die numbered 1 to 6 is rolled . Find the probability that in the roll of the results is an odd number or less than 4

Mathematics
1 answer:
stellarik [79]2 years ago
3 0

Answer:

4/6 or 66%

Step-by-step explanation:

Odd numbers from 1 to  6 are: 1, 3, 5

Numbers less than 4 are: 1, 2, 3

So there are  4/ 6 possible outcomes.

So the probability is 4/6 or 66%.

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g A psychic was tested for extrasensory perception (ESP). The psychic was presented with cards face down and asked to determine
diamong [38]

Answer:

Step-by-step explanation:

Hello!

The objective is to test ESP, for this, a psychic was presented with cards face down and asked to determine if each of the cards was one of four symbols: a star, cross, circle, square.

Be X: number of times the psychic identifies the symbols on the cards correctly is a size n sample.

p the probability that the psychic identified the symbol on the cards correctly

You have to calculate the sample size n to estimate the proportion with a confidence level of 95% and a margin of error of d=0.01

The CI for the population proportion is constructed "sample proportion" ± "margin of error" Symbolically:

p' ± Z_{1-\alpha /2} * (\sqrt{\frac{p'(1-p')}{n} } )

Where  d= Z_{1-\alpha /2} * (\sqrt{\frac{p'(1-p')}{n} } ) is the margin of error. As you can see, the formula contains the sample proportion (it is normally symbolized p-hat, in this explanation I'll continue to symbolize it p'), you have to do the following consideration:

Every time the psychic has to identify a card he can make two choices:

"Success" he identifies the card correctly

"Failure" he does not identify the card correctly

If we assume that each symbol has the same probability of being chosen at random P(star)=P(cross)=P(circle)=P(square)= 1/4= 0.25

Let's say, for example, that the card has the star symbol.

The probability of identifying it correctly will be P(success)= P(star)= 1/4= 0.25

And the probability of not identifying it correctly will be P(failure)= P(cross) + P(circle) + P(square)= 1/4 + 1/4 + 1/4= 3/4= 0.75

So for this experiment, we'll assume the "worst case scenario" and use p'= 1/4 as the estimated probability of the psychic identifying the symbol on the card correctly.

The value of Z will be Z_{1-\alpha /2}= Z_{0.975}= 1.96

Now using the formula you have to clear the sample size:

d= Z_{1-\alpha /2} * (\sqrt{\frac{p'(1-p')}{n} } )

\frac{d}{Z_{1-\alpha /2}} = \sqrt{\frac{p'(1-p')}{n} }

(\frac{d}{Z_{1-\alpha /2}})^2 =\frac{p'(1-p')}{n}

n*(\frac{d}{Z_{1-\alpha /2}})^2 = p'(1-p')

n = p'(1-p')*(\frac{Z_{1-\alpha /2}}{d})^2

n = (0.25*0.75)*(\frac{1.96}{0.01})^2= 7203

To estimate p with a margin of error of 0.01 and a 95% confidence level you have to take a sample of 7203 cards.

I hope this helps!

5 0
3 years ago
Read 2 more answers
577 rounded to the nearest ten
anygoal [31]

The correct answer 580

Hope this helps

7 0
2 years ago
Read 2 more answers
Given that ABCD congruent to PQRS, solve for m<br><br><br> A.0.5<br> B.2.5<br> C.3<br> D.5
34kurt
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5
3 0
3 years ago
Fide the volume and round to the nearest tenth . Please help I will give you brainless
devlian [24]

Answer:

46

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Airline companies raise and lower their ticket prices based on the supply and demand. Due to high numbers of fliers, one company
vovikov84 [41]
The raised price represents 110% of the original price (100% plus the extra 10%)

A percentage is converted into a decimal multiplier by dividing by 100:
\frac{110}{100}  = 1.10

To clarify the final stage, consider this (where n is the original price):
n * 1.10 = 192.50
1.10n = 192.50

From here, basic algebraic rules make solving for n easy:
n =  \frac{192.50}{1.10} = 175

Therefore the original price of a ticket was $175

3 0
3 years ago
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