Here is a trick that not a lot of people know
(# of terms)*(first+last)/2
(in case you don't know, * means multiply and / means divide)
Answer:
The probability P of a day with no perceptible earthquakes is 0.0821.
Step-by-step explanation:
We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.
<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>
where x = number of outcomes occurring
λ = mean number of occurrences
(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,
P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!
= ((0.0821)*1)/1
P(X=0) = 0.0821
The probability P of a day with no perceptible earthquakes is 0.0821.
explain more for me to understand better pls
Answer:
0.35(800)=x
x=number of tickets sold in advance
Step-by-step explanation:
