Answer:
The value of a function is the actual calculation done at a certain point. The limit is - roughly speaking - the value at points that are “arbitrarily close” to the same point. For most commonly used functions, the value of a function at a point, and the limit at the same point, is the same - at least for most values.
Answer:
The numbers are 18 and 91
Step-by-step explanation:
You can translate the information to two equations:
<em>a value 5 times a smaller number is 1 less than a larger number</em>
5a = b - 1
<em>their difference is 73</em>
b - a = 73
Then you should merge one equation into the other, thereby eliminating one variable. You can do this any way you want. I choose to rewrite the first equation as:
b = 5a + 1
Now I can write 5a+1 in the second equation at the place where b was:
5a + 1 - a = 73
It is now an equation with only one variable, solve by simplifying
4a = 72
a = 18
Now b can be found using b = 5a + 1
b = 91
Answer:
A) -5 / 6
Step-by-step explanation:
Answer: 123.5 centimeters
Step-by-step explanation:
Let sum of observations be S and number of observations be n.
Average A=
The average height of 4 children is (15h-3)
Also, when two more children join the group with heights of (10h+46) centimeters and (14h-16) centimeters the sum of heights of 6 children will be
Now, Average height of 6 students=
At h=9
Average height of 6 students=
Answer:
= A(t) = 120000(1.06)^t t = 1 year
We just add ^12 to equal 1/12 months.
Then use the notation below.
Step-by-step explanation:
We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.
For one year, t = 1, we want it to grow 6% = 1.06
Yearly Rate of Growth annual equation: = 7200
P(i) 7200/ 120000 x 100% = 6% per year growth rate
the yearly growth factor is 1 + appreciation rate = 1+i =1+0.06= 1.06
So time in years can be added to t
= A(t) = 120000(1.06)^t t = 1 year
The yearly growth factor = 1.06
To equate monthly we add the exponent t*12*1/12 before 120000(1.06)^t
then add 1/12 to replace ^t = monthly, or just keep the t= time
A(t) = 120000(1.06)^12t
