The intersecting secant theorem states the relationship between the two intersecting secants of the same circle. The given problems can be solved using the intersecting secant theorem.
<h3>What is Intersecting Secant Theorem?</h3>
When two line secants of a circle intersect each other outside the circle, the circle divides the secants into two segments such that the product of the outside segment and the length of the secant are equal to the product of the outside segment other secant and its length.
a(a+b)=c(c+d)
1.)
6(x+6) = 5(5+x+3)
6x + 36 = 25 + 5x + 15
x = 4
2.)
4(2x+4)=5(5+x)
8x + 16 = 25 + 5x
3x = 9
x = 3
3.)
8x(6x+8x) = 7(9+7)
8x(14x) = 112
112x² = 112
x = 1
4.)
(x+3)² = 16(x-3)
x² + 9 + 6x = 16x - 48
x² - 10x - 57 = 0
x = 14.0554
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35 is the first answer (BAE ~ DAC)
36. We must divide 20 by 2 to get 10 because all the other sides are 2x the size. 3x-5=10 (Add 5) 3x=15 (Divide by 3) x=5 so the last answer choice is correct.
Answer:
(0,-5)
Step-by-step explanation:
You just have to find the middle of each one
From -8 to 8 there are 16 numbers so you divide 16 by 2 which would be 8 and add that to -8 giving you 0
From -10 to 0 there are 10 numbers divided by 2 is 5 so you add 5 to -10 giving you -5
This makes your midpoint (0,-5)
Answer:
C: perpendicular lines
Step-by-step explanation:
Answer:
The value of s=10
Step-by-step explanation:
11+(-1)=10
