Answer:
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Step-by-step explanation:
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This is obviously a problem for system of two equations.
Let
Z=number of zebras (4 legged)
P=number peacocks (2 legged).
We know that
P=8-Z (total of 8 animals)
and
4Z+2P=4Z+2(8-Z)=28
expand and solve for Z
4Z+16-2Z=28
2Z=12
Z=6 There are 6 zebras.
Another way to solve, without pen and paper:
if all are zebras, there are 4*8=32 legs, or 4 legs too many.
Each exchange with a peacock reduces 2 legs, so we exchange 2 zebras with 2 peacocks to get 6 zebras.
Using the binomial distribution, it is found that there is a 0.056 = 5.6% probability that more than 7 will make a purchase.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 12 customers, hence n = 12.
- The probability of any of them making a purchase is of p = 0.4.
The probability that more than 7 will make a purchase is given by:
P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12).
Hence:
Then:
P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.042 + 0.012 + 0.02 + 0 + 0 = 0.056.
0.056 = 5.6% probability that more than 7 will make a purchase.
More can be learned about the binomial distribution at brainly.com/question/24863377
Answer:
8, -8 and 1
Step-by-step explanation:
Answer:
Answer Choices B and E on edge 2021
Step-by-step explanation:
B. A good first step for solving the equation is to subtract 0.5 from both sides of the equation
E. The negative case of this equation is x-12=-0.75