-- There is nothing on the list of choices that you provided that has no mass.
-- There are no "things" that have no mass. Every sample of a liquid, a gas,
or a solid has mass, even if it's only an atom or two.
I think the only possible items you could name that have no mass would be
spiritual, conceptual, or sensory ones, like maybe ...
-- idea
-- conviction
-- belief
-- concept
-- image
-- sound
-- illusion
-- impression
-- agreement
-- inclination
-- tendency
-- sparkle
-- tingle
-- pain
Things like that.
Lead would have greater mass than silver coz density of lead is higher
density of lead is 11.3, silver is 10.49
so it would be 11.4/10.49 = 1.08
means that lead it would have 1.08 times mass of silver
to be exact 1 cubic cm of silver would have mass 10.49 gr and lead cube would have mass 11.4 gr
The difference between both is that electric circuits makes use of relays, lighting controls, door bells e.t.c, whereas, electronic circuits deal with semiconductors that include transistors and integrated circuits.
Two examples are Smoke Detectors and Electric Toasters.
Now, the examples of two situations where both circuits are used together are;
1) Smoke Detector; In smoke detectors, there is the aspect of power which is the battery used to power the device and that operates with an electric circuit whereas the detector used to detect the smoke and make it beep is based on an electronic circuit.
2) Electric Toaster; The elements of the toaster used to heat materials operates on the principle of electric circuits while the timer used to stop the toasting is based on the principle of electronic circuits.
Read more here; brainly.com/question/24509929
Answer:
Explanation:
Given that,
Force is downward I.e negative y-axis
F = -2 × 10^-14 •j N
Magnetic field is westward, +x direction
B = 8.3 × 10^-2 •i T
Charge of an electron
q = 1.6 × 10^-19C
Velocity and it direction?
Force in a magnetic field is given as
F = q(V×B)
Angle between V and B is 270, check attachment
The cross product of velocity and magnetic field
F =qVB•Sin270
2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2
Then,
v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)
v = 1.51 × 10^6 m/s
Direction of the force
Let x be the direction of v
-F•j = v•x × B•i
From cross product
We know that
i×j = k, j×i = -k
j×k =i, k×j = -i
k×i = j, i×k = -j OR -k×i = -j
Comparing -k×i = -j to given problem
We notice that
-F•j = q ( -V•k × B×i)
So, the direction of V is negative z- direction
V = -1.51 × 10^6 •k m/s