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vampirchik [111]

3 years ago

7

A 4800 Watt heater is supposed to be plugged into a 120 volt outlet to work correctly. If the heater was plugged into a 90 volt

source instead, the amount of heat produced would

1 answer:

dedylja [7]3 years ago

3 0

Answer:

3600

Explanation:

90 of 120 is 3/4 so 4800 - 1200 is 3600.

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What is defined as a material resistance to the transmission of light waves flashcards?

seraphim [82]

This property is called "Opacity".

The question is worded in a difficult way. A more easily understood wording of this question would be:

"<em>What is the name of the property of a material that prevents light passing through?"</em>

3 0

3 years ago

Fire could be considered a living thing

dedylja [7]

anything that contains one cell of life is considered a living thing, a fire however does not contain any cells so it is not considered a living thing/organism

hope this helped you :)

5 0

3 years ago

Two electric charges qa = 1. 0 μc and qb = - 2. 0 μc are located 0. 50 m apart. how much work is needed to move the charges apar

melisa1 [442]

The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.

We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.

We have to calculate much work is needed to move the charges apart and double the distance between them.

<h3>What s the formula to calculate the Potential Energy of a system of two charges (say 'q' and 'Q') separated by a distance 'r' ?</h3>

The potential energy of the system of two charges separated by a distance is given by -

$U = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}$

In order to solve this question, it is important to remember the work - energy theorem which states -

"The change in the energy of the body is equal to work done on it"

Hence, using this work -energy theorem in the question given to us we get -

$U_{f} -U_{i} =W_{net}$

In our case -

$U_{f} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r}\\\\U_{i} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W=\frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r} - \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W = \frac{qQ}{4\pi\epsilon_{o}r} (\frac{1}{2} -1)\\\\W = 9\times 10^{9}\times \frac{1 \times 10^{-6} \times 2\times10^{-6} }{0.5} \times \frac{-1}{2}$

W = 0.018 joules

Hence, the total work done should be 0.018 joules.

To solve more question on potential energy, visit the link below -

brainly.com/question/15014856

#SPJ4

4 0

2 years ago

How are progression and variation similar?

borishaifa [10]

Answer:

c

Explanation:

3 0

3 years ago

In 1780, in what is now referred to as "Brady's Leap," Captain Sam Brady of the U.S. Continental Army escaped certain death from

zysi [14]

The minimum speed with which Captain Brady had to run off the edge of the cliff to make it safely to the far side of the river is around 6 meters per second.

<h3>Further explanation</h3>

This is a free fall 2-dimensional type of problem, therefor we can write equations for both dimensions which model the fall of captain Brady. Let's call <em>x </em>the distance travelled by the captain on the horizontal direction and <em>y </em>the distance travelled on the vertical direction.

Lets suppose that Brady jumped with a complete horizontal velocity from a point which we will call the origin (meaning zero horizontal and vertical displacement), and let's call <em>ta</em> the time it took for captain Brady to reach the river (meaning the time he spent on the air). The equations of motion for the captain will be:

$x= V \cdot t$

$y= - \frac{g \cdot t^2}{2}$

We know that at time <em>ta</em> the captain would have traveled 6.7 m on the horizontal direction, and 6.1 m in the vertical direction. Therefor we can write that:

$6.7= V \cdot ta$

$-6.1= - \frac{g \cdot {ta}^2}{2}$

Which gives us a system of 2 equations and 2 unknowns (<em>V</em> and <em>ta</em>). From the second equation we can solve for <em>ta</em> as:

$ta = \sqrt{\frac{2 \cdot 6.1}{g}} =1.12 s$

And solving for <em>V</em> on the first equation, we find that:

$V= \frac{6.7}{1.12} = 5.98 \frac{m}{s}$

Which is almost 6 meters per second.

<h3>Learn more</h3>

Free fall of an arrow: brainly.com/question/1597396
Concept of free fall: brainly.com/question/1708231

<h3>Keywords</h3>

Free fall, projectile, gravity

7 0

3 years ago

Read 2 more answers