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jarptica [38.1K]
3 years ago
11

The process of naming broad product-markets and then dividing them in order to select target markets and develop suitable market

ing mixes is called:
A. market penetration
B. market segmentation
C. market development
D. market research
Physics
1 answer:
sp2606 [1]3 years ago
7 0
<span>C. market development

</span>The process of naming broad product-markets and then dividing them in order to select target markets and develop suitable marketing mixes is called:<em><u>
MARKET DEVELOPMENT

NOT:
</u></em>
<em><u /></em><u />A. market penetration
B. market segmentation
<span>D. market research</span><em><u>
</u></em>
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A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic
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Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

to find out

mass of composite lump

solution

we know energy is conserved so

so m1 = m2 = m0 that is 4kg

and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c²  = Mc²    ..........................1

that why here

|v(1)| = |v(2)| = 3/5 c        ......................2

and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

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M = 10 kg

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7 0
4 years ago
If you pour hot soup into a bowl, and the bowl stays cool to the touch, you can assume that...
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Answer:

The soup still is cool, or since its recent it will take a while to get warmer

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3 years ago
A 1.1 kg block is initially at rest on a horizontal frictionless surface when a horizontal force in the positive direction of an
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Answer with Explanation:

Mass of block=1.1 kg

Th force applied on block is given by

F(x)=(2.4-x^2)\hat{i}N

Initial position of the block=x=0

Initial velocity of block=v_i=0

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Work energy theorem:

K_f-K_i=W

Where K_f=Final kinetic energy

K_i=Initial kinetic energy

W=Total work done

Substitute the values then we get

K_f-0=\int_{0}^{2}F(x)dx

Because work done=Force\times displacement

K_f=\int_{0}^{2}(2.4-x^2)dx

K_f=[2.4x-\frac{x^3}{3}]^{2}_{0}

K_f=2.4(2)-\frac{8}{3}=2.13 J

Hence, the kinetic energy of the block as it passes thorough x=2 m=2.13 J

b.Kinetic energy =K=2.4x-\frac{x^3}{3}

When the kinetic energy is maximum then \frac{dK}{dx}=0

\frac{d(2.4x-\frac{x^3}{3})}{dx}=0

2.4-x^2=0

x^2=2.4

x=\pm\sqrt{2.4}

\frac{d^2K}{dx^2}=-2x

Substitute x=\sqrt{2.4}

\frac{d^2K}{dx^2}=-2\sqrt{2.4}

Substitute x=-\sqrt{2.4}

\frac{d^2K}{dx^2}=2\sqrt{2.4}>0

Hence, the kinetic energy is maximum at x=\sqrt{2.4}

Again by work energy theorem , the  maximum kinetic energy of the block between x=0 and x=2.0 m is given by

K_f-0=\int_{0}^{\sqrt{2.4}}(2.4-x^2)dx

k_f=[2.4x-\frac{x^3}{3}]^{\sqrt{2.4}}_{0}

K_f=2.4(\sqrt{2.4})-\frac{(\sqrt{2.4})^3}{3}=2.48 J

Hence, the maximum energy of the block between x=0 and x=2 m=2.48 J

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The Sahara. The largest desert_____________________ on the planet. A searing wilderness the size of the _____________________. T
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Because of its level of hotness, it is considered very challenging to explorers.

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4 years ago
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