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ELEN [110]
3 years ago
7

7. Answer each of the following questions if the student applied a 550N force to a 100kg box on the same surface. What would be

the magnitude of the box's acceleration?
Physics
1 answer:
blagie [28]3 years ago
5 0
F=ma
550=100a
a=550/100
a=5.5 m/s²
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A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
3 years ago
In scientific notation, (6.2 x 10^4) x (3.3 x 10^2 ) equals ____________________.
castortr0y [4]
You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.
5 0
3 years ago
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ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

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3 years ago
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Novay_Z [31]
<span>The correct answer is: Mechanical Energy

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