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3 years ago

Identify the hyperbolas (represented by equations) whose centers are at (2, 1)

1 answer:

5 0

When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.

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Which pair of undefined terms is used to define a ray

IgorC [24]

Whats the options please?

6 0

3 years ago

How can you tell if a number is rational and irrational??

kompoz [17]

All numbers that are not rational are considered irrational. An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point.

4 0

2 years ago

Read 2 more answers

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

2 years ago

Side and angle properties of a parallelogram (level 2). NO LINKS!!!

gogolik [260]

Answer:

Hello,

If we look at the solution we can calculate this very easily

A is 40

B is 121

C=y

D=x

THe answer

x=46

y=13

z= 116

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

An arc of length 15ft subtends a central angle 0 in a circle of radios 9ft. Find measure of 0 in degrees

Kisachek [45]

Answer:

95.49°

Step-by-step explanation:

The arc length formula is s = rФ, where r is the radius and Ф is the central angle in radians. Here, r = 9 ft and s = 15 ft. Thus, the central angle Ф is

Ф = (15 ft) / (9 ft) = 5/3 radians, or

5 rad 180°

------- * ---------- = 95.49°

3 π rad

6 0

3 years ago