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lord [1]
4 years ago
8

Identify the hyperbolas (represented by equations) whose centers are at (2, 1)

Mathematics
1 answer:
weqwewe [10]4 years ago
5 0
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
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Solve for r and t:<br> 6r - 3t = 6<br> 6r + 8t = -16
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Multiply the first equation with (-1)
you should get this

-6r + 3t = -6
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11t = -22

divide by 11

t = -2

substitute 

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3 years ago
You want to put a fence around your field. The cost of fencing is $60 per meter. The
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Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
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-> Width of rectangular field = 25m
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-> w = $1500
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-> 2 x $1500
-> $3000

Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000


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