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Mekhanik [1.2K]
3 years ago
12

How many 1/2 cup servings are in 3/4cups of yogurt? (in simplest fraction form)

Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

3/2

Step-by-step explanation:

(3/4)/(1/2)=(3/4)(2/1)=6/4=3/2

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Please someone answer this!
Kaylis [27]

Answer: 108$

Step-by-step explanation:

5 0
3 years ago
What is the answer to 2x to the power of 2 +x +1=0
KonstantinChe [14]

Answer:

x=-1

Step-by-step explanation:

x+1=0(squared).

x+1=0 (anything raise to the power 0 is 0

collect like terms =x=-1

therefore x=-1

4 0
3 years ago
What is the range of y=sec^-1(x)?
Bingel [31]
Assuming that the x is not part of the ^-1 the range would be 

[0,π/2) U (π/2,<span>π]</span>
3 0
3 years ago
Read 2 more answers
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
Please help me with Questions 1 and 3 thank you
notka56 [123]

1) In a proportion: y/x=k

k is your constant of proportionality.

x is your independent variable and y is your dependent variable.

Since you need 3 oz of flour for each 2 oz of sugar, y=3 and x=2.

So k=1.5   (3/2)

3)

a) y/x as a showed above. This question is very similar to #1.

b) y/x=k

5 0
3 years ago
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