Hey there!:
Ksp =(Mg⁺²)(2F⁻)²
Ksp = (1.18*10⁻³)(2*1.18*10⁻³)²
Ksp = 6.57*10⁻⁹
Hope that helps!
KE = mv²/2
m=2*KE/v²
v=50 m/s
KE=500J
m=2*KE/v² =2*500/50²=1000/2500= 0.4 kg
Answer:
Your answer is C
Explanation:
When an acid and base react, the acidic hydrogen ion and the basic hydroxide ion in each acid and base neutralize each other and form water. Meanwhile the conjugate base and conjugate acid (the leftover compounds) react to form an ionic molecule, or a salt. (In chemistry, when an anion and a cation form an ionic bond the new molecule is called a salt). Hope this helps!
Answer : 0.14 mL of sterile water should be added to 700 mg of kanamycin.
Explanation : We know that 5 mL of sterile water has to be added to 1 gram of kanamycin so we have to find for 700 mg;
We can use the comparison formula here, where the unknown volume of sterile water in mL can be calculated;
700 mg / (1000 mg X 5 mL) = 0.14 mL
Hence, 0.14 mL will be added to 700 mg of karamycin.
These readings suggest the balance is: precise accurate neither accurate nor precise accurate and precise