Mendeleev's periodic table of elements was created in 1901. O A. True O B. False

Which is the best method for organizing information collected in an investigation? Plz help

Elden [556K]

Construct a table i think

7 0

3 years ago

Read 2 more answers

Help me please!!!!!!!!

alekssr [168]

Answer:

The element is CARBON

The number 6 refers to the ATOMIC NUMBER

the numbers 12, 13, and 14 refer to the ATOMIC MASS

how many protons and neutrons are in the first isotope?

6. 6

how many protons and neutrons are in the second isotope?

6. 7

how many protons and neutrons are in the third isotope?

6. 8

you are welcome :)

8 0

2 years ago

I need the answer please

dlinn [17]

Answer:

Na+ the answer is A

Explanation:

6 0

3 years ago

Read 2 more answers

Traveling at the speed of light - how long would it take, in years, to reach the top of the pile of balls? Show all calculations

marusya05 [52]

The time taken for the object to reach to top of pile is 0.012 year.

<h3>Time of motion </h3>

The time taken for the object to reach to top of pile is calculated as follows;

time of motion = distance traveled/speed

time of motion = (1.1 x 10¹⁴ x 10³ m)/(3 x 10⁸ m/s)

where;

speed of light = 3 x 10⁸ m/s

time of motion = 3.67 x 10⁵ sec = 0.012 year

Thus, the time taken for the object to reach to top of pile is 0.012 year.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

7 0

2 years ago

An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of

RSB [31]

Answer:

$V=0.0310L=3.10mL$

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

$n_{acid}=n_{KOH}$

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

$n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol$

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

$V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL$

Best regards!

7 0

3 years ago