Explanation:
Here,
- Initial velocity (u) = 0 (as it starts from rest)
- Final velocity (v) = 60 km/h
- Time taken (t) = 15 min
<u>C</u><u>o</u><u>n</u><u>v</u><u>e</u><u>r</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>the</u><u> </u><u>quanti</u><u>ties</u><u> </u><u>into</u><u> </u><u>its</u><u> </u><u>standard </u><u>form</u><u> </u><u>:</u>
→ v = 60 km/h
→ v = ( 60 × ) m/s
→ v = ( 10 × ) m/s
→ v = m/s
→ <u>v = 16.66 m/s</u>
Also,
→ t = 15 minutes
→ t = (15 × 60) seconds
→<u> t = 900 seconds</u>
<h3><u>C</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>accele</u><u>ration</u><u> </u><u>:</u></h3>
★ v = u + at
- v is final velocity
- a is acceleration
- u is initial velocity
- t is time
→ 16.66 = 0 + 900a
→ 16.66 - 0 = 900a
→ 16.66 = 900a
→ = a
→ 0.0185 m/s² = a
∴ Acceleration is 0.0185 m/s².
<h2>_________________________</h2>
<h3><u>C</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>distan</u><u>ce</u><u> </u><u>cover</u><u>e</u><u>d</u><u> </u><u>:</u></h3>
★ v² - u² = 2as
- v is final velocity
- a is acceleration
- u is initial velocity
- s is distance
→ (16.66)² - (0)² = 2 × 0.0185 × s
→ 277.5556 - 0 = 0.037s
→ 277.5556 = 0.037s
→ = s
→ 7501.50 m = s
∴ Distance covered is 7501.50 m .
Answer:
(a). The weight of spacecraft at height 6450 km is .
(b). The weight of spacecraft at height 33700 km is 182.46 N.
Explanation:
Given that,
Radius of earth = 6450 km
Weight of spacecraft = 7070 N
We need to calculate the weight of the spacecraft at a height 6450 km above Earth’s surface
Using formula of weight
Where, W = weight of spacecraft
h = height
Put the value into the formula
(b). We need to calculate the weight of spacecraft at height 33700 km
Using formula of weight
Hence, (a). The weight of spacecraft at height 6450 km is .
(b). The weight of spacecraft at height 33700 km is 182.46 N.
Answer:
<h2>15m/s</h2>
Explanation:
Step one:
given data
acceleration a=4m/s^2
final velocity v=35m/s
time t=5 seconds
Step two:
Required
initial velocity u=?
Applying the first equation of motion
v=u+at
substituting we have
35=u+4*5
35=u+20
u=35-20
u=15 m/s
The initial velocity is 15m/s
<span>The heat energy is being transferred between the two substances by thermal conduction. Because the hot coffee is at a different temperature to the mug, heat energy flows between them so that they reach thermal equilibrium, or the same temperature. This kind of heat transfer always happens from hotter temperatures to cooler temperatures.</span>
Answer:
umm i really don't know... sorry
Explanation: