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mina [271]
3 years ago
10

Meredith walks from her house to a bus stop that is 260 yards away. If Meredith is 29 yards from her house, how far is she from

the bus stop? 231 Correct yards If Meredith is 204.8 yards from her house, how far is she from the bus stop? 55.2 Correct yards Let the variable x represent Meredith's varying distance from her house (in yards). As Meredith walks from her house to the bus stop, the value of x varies from 0 Correct to 260 Correct . How many values does the variable x assume as Meredith walks from her house to the bus stop? 3 Incorrect
Physics
1 answer:
slega [8]3 years ago
3 0

Answer:

a) 231 yards

b) 55.2 yards

c) 0 yards to 260 yards

d) Infinite values

Explanation:

This situation can be described as a horizontal line that begins at point P_{1}=0 yards (Meredith's house) and ends at point P_{2}=260 yards (Bus stop). Where x is the varying distance from her house, which can be calculated in the following way:

x=Final Position - Initial Position

or

x=x_{f} - x_{i}

a) For the first case Meredith is at position x_{i}=29 y and the bus stop at position x_{f}=260 y. So the distance Meredith is from the bus stop is:

x=260 y - 29 y=231 y

b) For the second case the initial position is x_{i}=204.8 y and the final position x_{f}=260 y. Hence:

x=260 y - 204.8  y=55.2  y

c) If we take Meredith's initial position at her house  x_{i}=0 y and her final position at the bus stop  x_{f}=260 y, the value of  x varies from 0 yards to 260 yards.

d) As Meredith walks from her house to the bus stop, the variable x assumes infinite values, since there are infinite position numbers from x=0 yards to x=260 yards

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