If circle 2 were a glide reflection of circle 1, what transformations would be involved
1 answer:
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Answer:
x ≈ - 6.74, 0.74
Step-by-step explanation:
x² + 6x - 5 = 0 ( add 5 to both sides )
x² + 6x = 5
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = 5 + 9
(x + 3)² = 14 ( take square root of both sides )
x + 3 = ± ( subtract 3 from both sides )
x = - 3 ±
Then
x = - 3 - ≈ - 6.74 ( to the nearest hundredth )
x = - 3 + ≈ 0.74 ( to the nearest hundredth )
The formula to find the volume of a prism is V=Bh (Volume = Base x height). Let's plug in the dimensions you were given:
V=Bh
V=(5)(10)
V=50 {tex] ft^{2} [/tex]
To find the new volume of the dilated prism, cube the dilated factor, then multiply by the volume you just found (old volume):
New Volume = (
)(Old Volume)
V = (
)³·50
V = (
V = 86.4
V=Bh
V=(5)(10)
V=50 {tex] ft^{2} [/tex]
To find the new volume of the dilated prism, cube the dilated factor, then multiply by the volume you just found (old volume):
New Volume = (
V = (
V = (
V = 86.4