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Citrus2011 [14]
3 years ago
12

Please help me please! I’m stuck, and I can’t figure this out. Please include the form in your answer! No phony answers pls!

Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

x ≈ - 6.74, 0.74

Step-by-step explanation:

x² + 6x - 5 = 0 ( add 5 to both sides )

x² + 6x = 5

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 5 + 9

(x + 3)² = 14 ( take square root of both sides )

x + 3 = ± \sqrt{14} ( subtract 3 from both sides )

x = - 3 ± \sqrt{14}

Then

x = - 3 - \sqrt{14} ≈ - 6.74 ( to the nearest hundredth )

x = - 3 + \sqrt{14} ≈ 0.74 ( to the nearest hundredth )

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Tell whether each sentence below is true or false.
krek1111 [17]

Answer:

1. is True

2. is true

Step-by-step explanation:

1. the reason they are both true is that they are all part of the quadrilaterals and because the 4 sides in each shape, but a trapezoid has one pair of parallel sides. Which makes both sentences true! Hope it helps :)

6 0
2 years ago
Read 2 more answers
Moesha is (3g+1) years old and shanti is twice moesha age. find the sum of the ages of moesha and shanti in 2 years time.
SpyIntel [72]

Answer:

1.  In 2 years, sum of the ages of Moesha and Shanti = 9g + 7

2.  When Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

3.  4 years ago, Moesha was 12 years old and Shanti was 28 years old if g = 5.

Step-by-step explanation:

Moesha's age = 3g + 1

It is given that Shanti's age is twice Moesha's age.

So, Shanti's age = 2(3g + 1)

= 6g + 2

In 2 years time,

Moesha's age = (3g + 1) + 2 = 3g + 3

Shanti's age = (6g + 2) + 2 = 6g + 4

Hence, sum of the ages of Moesha and Shanti = (3g + 3) + (6g + 4)

= 9g + 7

Moesha's age will be twice her present age in 3g + 1 years.

After 3g + 1 years, Shanti's age will be (6g + 2) + (3g + 1) = 9g + 3 years.

= 3(3g + 1)

= thrice Moesha's present age

Hence, when Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

If g = 5,

Moesha's present age = 3g + 1

= 3(5) + 1

= 15 + 1

= 16

Shanti's present age = 6g + 2

= 6(5) + 2

= 30 + 2

= 32

Hence, 4 years ago, Moesha was 16-4 = 12 years old and Shanti was 32-4 = 28 years old.


8 0
3 years ago
In a group of students, 30 played chess, 19 played volleyball, 25 played
saul85 [17]

Answer:

Explained below.

Step-by-step explanation:

Denote the events as follows:

<em>C</em> = chess

<em>V</em> = volleyball

<em>B</em> = basketball

The data provided is as follows:

n (C) = 30

n (V) = 19

n (B) = 25

n (C ∩ V) = 14

n (B ∩ V) = 8

n (B ∩ C) = 15

n (C ∩ V ∩ B) = 5

Consider the Venn diagram below.

The number of students who played only chess is marked in pink:

n (Only C) = 6

The number of students who played only volleyball is marked in blue:

n (Only V) = 2

The number of students who played only basketball is marked in orange:

n (Only B) = 7

The number of students who played all three is marked in grey:

n (C ∩ V ∩ B) = 5

5 0
4 years ago
Solve the system of equations<br><br> system
Korolek [52]

Answer:

(3, 3 )

Step-by-step explanation:

Given the 2 equations

3x - y = 6 → (1)

6x + y = 21 → (2)

Adding the 2 equations term by term will eliminate y, that is

(6x + 3x) + (y - y) = (21 + 6), that is

9x = 27 (divide both sides by 9 )

x = 3

Substitute x = 3 into either (1) or (2) and solve for y

Using (2), then

(6 × 3) + y = 21

18 + y = 21 ( subtract 18 from both sides )

y = 3

Solution is (3, 3 )

8 0
4 years ago
Read 2 more answers
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cestrela7 [59]
2xy + 5 - 8 + 3xy - y +7 + 3y = 5xy - 8 + 2y + 12
6 0
4 years ago
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