Answer:
p = 
and q = 
Step-by-step explanation:
Given equations:
2p - 3q = 4 -----------(i)
3p + 2q = 9 ------------(ii)
Let's solve this equation simultaneously using the <em>elimination method</em>
(a) Multiply equation (i) by 3 and equation (ii) by 2 as follows;
[2p - 3q = 4] x 3
[3p + 2q = 9] x 2
6p - 9q = 12 -------------(iii)
6p + 4q = 18 -------------(iv)
(b) Next, subtract equation (iv) from equation (iii) as follows;
[6p - 9q = 12]
<u> - [6p + 4q = 18] </u>
<u> -13q = -6 </u> -----------------(v)
<u />
<u>(c)</u> Next, make q subject of the formula in equation (v)
q =
(d) Now substitute the value of q = into equation (i) as follows;
2p - 3() = 4
(e) Now, solve for p in d above
<em>Multiply through by 13;</em>
26p - 18 = 52
<em>Collect like terms</em>
26p = 52 + 18
26p = 70
<em>Divide both sides by 2</em>
13p = 35
p =
Therefore, p = and q =
Answer:
8x^2 + 15x -9
Explanation:
Distribute and combine
Answer: 4) 157
Step-by-step explanation:
We know that there is no association between the grade level and the andedness, then we should find that the ratio between left handeds and right handed is the same for both grades.
In 7-th grade we have:
Left handed : 11
Right handed: 72
The ratio is 11/72 = 0.14
Then, the ratio for the 8-th graders must be about the same:
Left handed: 24
Right handed: X
Ratio: 24/X
Let's start with the bigger option, X = 157.
24/157 = 0.15
Ok, we now see that with the bigger option we obtained almost the same ratio (if we use the smaller values for X, we will get a ratio bigger than 0.15, so 0.15 is the better aproximation that we can find to the 0.14 of the 7-th graders)
Then the correct option is 4) 157
The only equation that works with x=-6 is A
159 i don’t know for sure tho
