All categories

3 years ago

Help please, thank you!❤️❤️

Mathematics

1 answer:

babunello [35]3 years ago

8 0

Answer and Step-by-step explanation:

8 and negative 4 (-4) would be the answer.

8b times -4b equals -32 $b^{2}$

8b + -4b equals 4b.

c in that diagram would equal -32, and B would equal 4.

#teamtrees #PAW (Plant And Water)

You might be interested in

What is 6 times 3 over 8? How do you do it? In a fraction and simplified?

Mademuasel [1]

First do 6 times 3=18 then divide by 8 to get 2.25

5 0

3 years ago

Read 2 more answers

a music store has 40 trumpets 39 clarinets 24 violins 51 fluites and 16 trambones in stock write each ratio in simplest gorm

disa [49]

Given:

A music store has the following:

40 trumpets

39 clarinets

24 violins

51 flutes

16 trombones

We will write the following ratios:

trumpets to violins =

$undefined$

6 0

1 year ago

What is the result of 4÷ 8/12 ? A. 1/6 B. 3/8 C. 3 D. 6 help me please ! thank you

IRINA_888 [86]

Answer:

D 6

Step-by-step explanation:

4/1 / 8/12

4/1 * 12/8

48 / 8 = 6

3 0

3 years ago

2x+3y=11, solve for y

lesya [120]

Hope it helps with your work

4 0

3 years ago

Read 2 more answers

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago