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Dmitry [639]
3 years ago
13

Which values of x are point(s) of discontinuity for this function? Function x = –4 x = –2 x = 0 x = 2 x = 4

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

x = –2

x = 0

x = 4

Step-by-step explanation:

e2020

Nadya [2.5K]3 years ago
6 0

Answer:

the answer is x=0 and x=2

Step-by-step explanation:

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11 + 13 =24
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Decorations for a seventh-grade dance take 1/6 of the student council's budget. entertainment takes 3/8 of the budget. what frac
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11/24 is left over

Step-by-step explanation:

1/6 + 3/8 = 13/24

24/24 - 13/24 = 11/24

11/24 of the budget is left over

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For the function y = 9x, what is the output value if 5 is the input value?
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If Amanda walks at an average speed of 2.72 miles per hour how long will it take her to walk 6.8 miles
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If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
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