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Natasha2012 [34]
3 years ago
15

Find all points of intersection of the given curves. (Assume 0 ≤ θ ≤ 2π and r ≥ 0. Order your answers from smallest to largest θ

. If an intersection occurs at the pole, enter POLE in the first answer blank.) r = 8 sin(2θ), r = 4

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,

∅8=345°

Step-by-step explanation:

Data

r = 8 sin(2θ), r = 4 and r=4

iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°

according the graph 2, the cut points are:

I quadrant:

0+15° = 15°

90°-15°=75°

II quadrant:

90°+15°=105°

180°-15°=165°

III quadrant:

180°+15°=195°

270°-15°=255°

IV quadrant:

270°+15°=285°

360°-15°=345°

No intersection whit the pole (0)

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Answer:

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Step-by-step explanation:

3x+5y=36

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Answer:

A) Length = 110.4 mm and width = 62.1 mm

B) A = 6855.84 mm²

C) length = 114.7 mm

width = 55.8 mm

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D) Screen with aspect ratio of 16:9 is bigger

Step-by-step explanation:

A) We are told that the aspect ratio of the phone screen = 16:9. This means that the ratio of the length to the width of the screen is 16:9.

To find the side length, we will say that;

length = 16x

width = 9x

Thus, since the edges are perpendicular, then we can use pythagoras theorem since we know that the diagonal is 127 mm

Thus;

(16x)² + (9x²)] = 127²

256x² + 81x² = 16129

337x² = 16129

x² = 16129/337

x = √(16129/337)

x = 6.9

Thus;

length = 16x = 16 × 6.9 = 110.4 mm

width = 9x = 9 × 6.9 = 62.1 mm

Length = 110.4 mm and width = 62.1 mm

B) area of screen is;

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A = 110.4 × 62.1

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C) We are told that the aspect ratio is now 18.5:9.

Thus;

length = 18.5x

width = 9x

Thus;

(18.5x)² + (9x²)] = 127²

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x² = 16129/423.25

x = √(16129/423.25)

x = 6.2

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width = 9x = 9 × 6.2 = 55.8 mm

Area = 114.7 × 55.8 = 6400.26 mm²

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Answer:

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