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3 years ago

Graph the following system of equations and find where they meet 3x + 5y = 36 y = 5x - 4

Mathematics

1 answer:

Over [174]3 years ago

4 0

Answer:

[2,6]

Step-by-step explanation:

3x+5y=36

5x-4=y

3x+5(5x-4)=36

3x+25x-20=36

28x-20=36

28x=56

x=2

5x-4=y

5*2-4=y

10-4=y

6=y

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Solve the equation for a a/c = d/r

Ghella [55]

Answer:

a=(d*c)/r

Step-by-step explanation:

a/c = d/r

a=(d/r) *c

a=(d*c)/r

6 0

3 years ago

Rachel rides her bike due east at 9 miles per hour. Amos rides his bicycle due north at 12 miles per hour. If they left from the

Svetach [21]

They will be 15 miles apart after one hour if they left the same point at the same time.

<h3>How do we measure and calculate the distance in Geometry?</h3>

The distance between two points in geometry can be calculated by using the Pythagoras theorem.

Mathematically, the Pythagoras theorem can be expressed as:

$\mathbf{d = \sqrt{x^2 +y^2}}$

where;

x and y are opposite and adjacent sides respectively.

$\mathbf{d = \sqrt{(9)^2 +(12)^2}}$

$\mathbf{d = \sqrt{81+144}}$

$\mathbf{d = \sqrt{225}}$

d = 15 miles

Therefore, we can conclude that they will be 15 miles apart after one hour if they left the same point at the same time.

Learn more about calculating the distance between two points here:

brainly.com/question/7243416

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5 0

2 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

4 years ago

What is 2s+(−4s) 2s+(−4s)?

algol13

It’s -4 because you need to like distribute then add like terms, etc.

3 0

3 years ago

How do you check the answer for the division problem eight divided by three hundred?

lawyer [7]

Answer:

you multiply the quotient times the divisor and your awnser should be the same as the dividend

Step-by-step explanation:

7 0

3 years ago